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- OSTP Pressure Distribution =: <br /> UNIVERSITY " - <br /> MinnesotaPoilution Design Worksheet <br /> Control Agency OF MINNESOTA <br /> Project <br /> ID:3 v 11.09.22 <br /> 1. Select Number of Perforated Laterals in system/zone: <br /> (Z feet is minimum and 3 feet is maximum spacing) `^ "u <br /> 2. Select Perforation Spacing: 3.0 ft <br /> toratirma Mo,irnum� Por sp:,c,!03'apart_ t;-2".of,rock <br /> 3. Select Perforation Diameter Size 7J32 in I _ <br /> G'01 rock <br /> 4. Length of laterals =Media Bed Length-2 Feet. Periorotio„sizing:•/;to/: P rf-aliw,SPadM,:2'To 3' <br /> 63 - 2ft = 61 ft Perforation can not be closer then 1 foot from edge. <br /> 5. Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 61 ft = ft 20 Spaces <br /> 6. Number of Perforations per Lateral is equal to 1.0 plus the Number-offPPerforation Spaces (Line 5). <br /> Perforations Per Lateral = 20 Spaces 1 = 21 Perfs.Per Lateral <br /> Check table below to verify the number of perforations per lateral guarantees less than a 10%discharge variation. The value is <br /> double if the a center manifold is used. <br /> Maximum Nu►rxr of Perforations Per Lateral to Guarantee c 10%Discharge Variation <br /> %61nc <br /> Peeforabons 7/32 Inch Perforations <br /> Pipe Diameter(inches) Perforation Spacing Pipe Diameter(inches) <br /> Perforation Spacing(Feet) 1 11' 11: 2 3 (Feet) t 11< 11t 2 3 <br /> 2 10 13 18 30 60 2 11 16 21 34 68 <br /> 2i1 8 12 16 28 54 2�11 10 14 20 32 64 <br /> 3 8 12 16 25 52 3 4 14 19 30 60 <br /> 3/16 Inch Perforations 1rr8 Inch Perforations <br /> Perforation Spacing(Feat) Pipe Dianne#er{inches) Perforation Spacing Pipe Diameter(inches) <br /> 1 ib: lit 2 3 (Feet) i I 1Si 112 2 3 <br /> 2 12 i$ 26 46 87 2 2f 33 44 74 149 <br /> 12 17 24 40 80 21! 20 30 41 69 135 <br /> 3 12 16 1 22 1 37 1 75 3 20 29 38 64 128. <br /> 7• Total Number of Perforations equals the Number of Perforations per Lateral (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> 21 Perf.Per Lateral X ��Number of Perf.Laterals = 63 Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforation. Recommended value is 4-10 ft2 per perforation. _ PorfanTbnOkcharpt former <br /> Does not apply to At-Grades Porf -ti-Di-*r <br /> rtoaa,rq .�. 'h. '1u `i <br /> Bed Area = Bed Width(ft)X Bed Length(ft) ,.o• oa o.,. 0.56 o_T,. <br /> 1.5 0.22 0.51 0.69 0.9 <br /> 10 <br /> it X 63 ft = 630 fir 2.e 0.26 0.59 0.00 1.04 <br /> Z5 0.29 0.6s 0.69 1.17 <br /> Square Foot per Perforation =Bed Area divided by the Total Number of Perforations (Line 7). 4.0 0.37 o ss 1.,s 1.47 <br /> 5.0 0.41 ;0.93 1 146 t.65 <br /> 630 = C� _ ,,mt pworao w[h 31161=b wll,iKh <br /> ftZ 63 perforations 10.0 ft2/perforations perforn-Ov <br /> Owetlitgs with 1 a inch perforatbc <br /> 9. Select Minimum Avera a Head: 1.0 ft 2 feet Other estahihhrncnn and MKTS wRh 3116 <br /> g ineh to 174 inch 9erroMtbro <br /> 5 feet O[her estaahMieMs and METS with tld inch <br /> perrorotioM <br /> 10. Select Perforation Discharge (GPM)based on Table III: 0.56 GPM per Perforation <br /> 11. Determine required Flow Rate by multiplying the Total Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br />