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Mound Design Worksheet (For flows up to 1200 gpd) <br /> All boxed rectangles must be entered,the rest will be calculated. <br /> A. FLOW Arifsti <br /> : maied Sewage Rawl in Gallons per Day <br /> Estimated 600 gpd(see figure A-1) nunwof <br /> or measured x 1.5(safety factor)= 0 gpd bedr00n Class I Class II Class III Class IV <br /> 2 300 225 180 60% <br /> B. SEPTIC TANK LIQUID VOLUMES 3 450 300 218 of the <br /> Septic tank capacity 2000 gallons(see figure C-1) 4 600 375 256 vogues <br /> 5 750 450 294 in the <br /> C. SOILS(Site evaluation data) 6 900 525 332 Gass I, <br /> 1. Depth to restricting layer= 2 feet 7 1050 600 370 0,or III <br /> 2. Depth of percolation tests= 12 inches 1 8 1 1200 1 675 1 408 1 cclurrru, <br /> 3. Texture I Silt Loam <br /> 4. Soil loading rate(see Figure D-33) 0.5 gpd/ft2 <br /> Percolation rate 1 35 IMPI <br /> 5. %Land Slope 4 % D-33: Absorption Width Sizing Table <br /> Percolation Rate Lo=,s Rate <br /> in Dlittum per Soil Texture Gallons Absorption <br /> C-1: Septic Tack Capacities tin i lonsl Inch per day per Ratio <br /> nip! - Clare root <br /> LlutdcapacitFsaerdans � n 1.20 too <br /> Number of Minimum Liquid Liquid ca acity midi Sa <br /> with disposal& Loamy Sand <br /> Bedrooms Capacity garbage disposal lift inside Fine Sana ____ <br /> S ISO <br /> S 16 to 30 Loam _ 0.60 200_ <br /> or less ! 11.2_ 1500 31 to 43 Silt Loam 0.50 240 <br /> It <br /> 3 or 4 1000 1500 2000 46 to 60 Sandy clay 0.45 267 <br /> 5 or 6 1500 21250 3000 Silty Clay Loam <br /> 7,8 or 9 2000 1 3000 t <br /> 61 to 120 Silty Clay 0.24 Soo <br /> sandy Oxy <br /> Clav <br /> flower thm 120' - <br /> 'Swum deeia w for a"soil*Mae to or or parts 3"v <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow(A)by 0.83 to obtain required area of rock layer: Item A x 0.83= <br /> 600 gpd x 0.83 ftygpd= 498.0 ft2 <br /> 2. Determine rock layer width =0.83 ft2/gpd x Linear Loading Rate(LLR)(see LLR chart) <br /> 0.83 ft2/gpd X 12 = 10.0 ft <br /> LLR Chart <br /> Perk Rate LLR <br /> <120 MPI <=12 <br /> >=120 MPI <=6 <br /> 3. Length of rock layer=area divided by width= <br /> 498 ft2 / 10 feet= 50.0 feet <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock <br /> 498 X 1 ft= 498.0 ft' <br /> 2. Divide ft3 by 27 ft3/yd3 to get cubic yards <br /> 498.0 ft' / 27 = 18.4 yd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 18.4 yd X 1.4 ton/yd3 = 25.8 tons <br /> F. ABSORPTION WIDTH <br /> 1. Absorption width equals absorption ratio(see Figure D-33)times rock layer width <br /> 2.4 x 10.0 ft = 24.0 ft <br />