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PRESSURE DISTRIBUTION SYSTEM - Trenches C:cotcnGlc rabnr e"na3f MI[wc. a!3' All boxed rectangles must be entered,the rest will be calculated. q" ,r-k P-f f-ting 3/16."-1/4" 4'.•rf VtL ming I.SS' 1. Select number of perforated laterals: 03 2. Select perforation spacing = 0ft E4: MmtlmLtrndlowlb4ertunbwofl/4-lnchperforaftm per lateral>o guaaMee<10%discharge vorlatlon 3. Since perforations should not be placed closer that 1 foot to pfffaakm the edge of the rock layer(see diagram), subtract 2 feet from (feen 11nch 1.251rfch 1.5kch ZOlrlch the rock layer length 2.5 8 14 18 28 50 -2ft= 48 ft 3.0 8 13 17 26 rock layer length 3-3 7 12 1 25 Y 9 40 � n 1s 5 23 5.0 1 6 1 10 1 14 22 4 Determine the number of spaces between perforations. Divide the length (3) by perforation spacing (2) and round down to nearest whole number. Perforation spacing = 48 ft/ 3 ft= 16 spaces 5. Number of perforations is equal to one plus the number of perforation spaces (4). *Check figure E-4 to assure the number of perforations per lateral guarantees < 10%discharge variation. 16 spaces+ 1 = 17 perforations/lateral 6. A. Total number of perforations= perforations per lateral (5) times number of laterals(1). 17 perfs/lat x 3 laterals = 51 perforations E-6: Perixa cn Dischape in ppm B. Calculate the square footage per perforation. Should be 6-10 s ft/ erf. Does not I to at-grades. perforation diameter q P apply 9 head Inches 1. Rock bed area= rock width (ft)x rock length (ft) (feet) 118 3116 7132 1/4 10 ft x 50 ft= 500 ft2 1.00 0.18 0.42 0.56 0.74 2. Square foot per perforation = Rock Bed Area/number of perfs (6) 500.0 ft' / 51 perfs = 9.8 ft2/pert 2.0b 0.26 0.59 0.80 1.04 5.0 0.41 0.94 1.26 1.65 7. Determine required flow rate by multiplying the total number use 1.orc.lfctrsirCa1edarrUy ncrrwt of perforations(6A) by flow per perforations (see figure E-6) n usp 2.G nkat r,-,.(c;r:1'rr � . 51 perfs x 1 0.56 gpm/perfs= 28.6 gpm 8. If laterals are connected to header pipe as shown in Figure E-1, to select minimum required lateral diameter; enter figure E-4 with perforation spacing (2) and number of perforations per lateral (5). Rgwo E-1:ManHold Looafed of End of Syst*m Select minimum diameter for perforated laterals= 02 inches 9. If perforated lateral system is attached to manifold pipeRgwehe Gnfer of the 9ysroE-2:Manifold Looafed " in tm near the center, like Figure E-2, perforated lateral length (3) and number of perforations per lateral (5)will be approximately one half of that in step 8. Using these values, select - minimum diameter for perforated lateral = 0 inches. �- I her erti h t hav completed this work in accordance with all applicable ord' an s, rules and laws. (signature) �02 (license#) (date)