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MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day <br /> Estimated 3e)0 gpd N ober ITMI Type 11 Type ID 1 Type <br /> of <br /> or measured x 1.5 = gpd. BedloornsIv <br /> 2 300 2u ]so <br /> B. SEPTIC TANK LIQUID VOLUMES a 6 0 37s° zz'S6ofthe valties <br /> ZS"L'r7AZ gallons 6 790500 52505 3332 Type 1. <br /> 7 1050 600 370 p or <br /> 8 1200 675 408 IIl <br /> C. SOILS(refer to site evaluation) Oollan s <br /> 1. Depth to restricting layer= inches .Z feet liquid capacity <br /> 2. Depth of percolation tests= ZZ inches B`r of "''adty ►iquidcatds"al .idta � <br /> �I�tY BYbsie disposal lift inside <br /> 3. Texture-XPercolation rate Z_mpi ow .1" ' <br /> 5 rK 61500 2250 3000 <br /> 4. Land slope /.Z % LLif 200DMW 4= <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> 3C>C5 gpd x 0.83 sq. ft./gpd =ZXO sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = /O ft. <br /> 3. Length of rock layer=area_width= <br /> sr?-aeW�gma revlp'ts a, <br /> Z67,-'0 sq. ft-_ 1!Z ft- _ ft• "a �.� <br /> .R* y �A <br /> �Y� 'r'Vaa.�.s-.a:s�*a <br /> Width /0 ft o s: o .sO q`VOD S a•: <br /> <120mpi <10' Length-�ft <br /> E. ROCK VOLUME <br /> >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; sq- ft. x <br /> ft. =ZX�cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu.yd. toget cubic yards; <br /> .1C0 cu. ft. =27=Z 4Z-f cu.yd. <br /> 3. Multiply cubic yards by 1.4 to get wei�ht of rock in tons,'? yd. x 1.4 <br /> ton/cu. yd. =/Mons. <br /> F. ABSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is-1-7 mpi Percolation RM is Gallons xatindfnhsorptim <br /> Texture `ASH Minuet per bicb Soil Textureper day per width to Rock <br /> (MM square foot Lays Yru m <br /> Faster 611110.1 coarse Sand 1.20 1.00 <br /> 0.1to 5 Sand 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; 0.I IDS Fine sand 0.60 2.00 <br /> d/ft2 6 w to <br /> sandy Loam 0.79 1.52 <br /> •- 16 30` loam .�. 0.60'� <br /> �r <br /> 31%o45 Sat I== 0.50 206 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer SJ-1120 Gay 020 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft'-. 40 gpd/ft2= Z• O <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> .Z xj,0 ft=eft <br />