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1998-010215 - new septic
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3280 Watertown Road - 32-118-23-44-0002/3
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1998-010215 - new septic
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Last modified
8/22/2023 4:42:10 PM
Creation date
8/21/2019 12:55:50 PM
Metadata
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Template:
x Address Old
House Number
3280
Street Name
Watertown
Street Type
Road
Address
3280 Watertown Road
Document Type
Septic
PIN
3211823440002
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Esdntned Sewage Flow to Oalims per My(0d) <br /> Estimated (,c) gpd gpd. sof Typo 1 Typo a type u1 'type ry <br /> or measured=x 1.5 =_ <br /> 2 300 las Iso .o. <br /> 3 130 300 219 •r <br /> B. SEPTIC TANK LIQUID VOLUMES s 50 iso 9 ' <br /> on <br /> -/000 gallons 7 tc o � 370 <br /> 9 1200 675 109 <br /> C. SOILS(refer to site evaluation) Nmbw ►�, .,� <br /> 1. Depth to restricting layer= z i 4 312 inches Bedroom � <br /> 2. Depth of percolation tests = a inches <br /> 3. Percolation rate 4.1 mpi 23 e<t� i,0 1.5 c <br /> 4. Land slope % «e '2.0000° 1.010 <br /> wsr 9 Sea fig.C.6 (s ls) <br /> D. ROCK LAYER DDYMNSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer.A x 0.83 - <br /> (,v -9 gpd x 0.83 sq.ft./gpd mcz sq. ft.+)o?o-5,1A r) <br /> 2. Select width of rock layer(10 feet or less) _ /o ft. <br /> 3. Length of rock layer= area+width= Rock Bed <br /> 4'? sq. ft.+ /o ft. = 5's ft. <br /> �3r• <br /> ��;�;; •,; t!�!; Idth 510 ft. <br /> r•r•r•r•r•r•r• r r r r•r•r• <br /> �- --+ <br /> E. ROCK VOLUME Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> �2 sq.ft.xLo<ft. _L-4 cu. ft. <br /> 2. Divide cu.ft.by 27 cu.ft:/cu. yd. to get cubic yards; <br /> ,,5,o L4 cu.ft• +27= -A ) _cu. yd. <br /> 3. Multiply.cubic yards by 1.4 to get weight of rock in tons; <br /> a,cu.yd.x 1.4 ton/cu. yd. = tons. <br /> F. ADSORPTION WIDTH -�� 10►41'� Width ftizinitLbit <br /> 1. Percolation rate in top 12 inches of soil is .I mpi �(mu��� pmit Texture <br /> r.. .►..r., <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Comm Sand 1.20 1.00 <br /> gpd/f6 120 1.00 <br /> ,`1 S 0.1 to 5 Fine Sand- 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1.52 <br /> 16 to 30 Loam 0.60 2.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer 31 to 45 silt Loam o50 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to <br /> 21 0 Cla�aLooam oza s 67 <br /> 61 1.20 gpd/ftz+ •y-<' gpd/fO = -a•L 2 Slower than 120 Cla - - <br /> ••Sdt 1tivinQ SOR at man d Rn�w vary fire w+d <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> ;w"-) x 10._ft=,;zi,.Z ft <br />
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