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MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day <br /> (god) <br /> Estimated�gpd Number Type I Type 11 Type M Type <br /> or measured x 1.5 = gpd. Iv <br /> 2 300 225 180 60% <br /> B. SEPTIC TANK LIQUID VOLUMES 4 3 450 305° 2z's6 ofd <br /> G ZSD gallons Val <br /> 6 7900 su 33z ues <br /> ra 1. <br /> 7 1050 600 370 U or <br /> 8 1200 675 408 W <br /> C. SOILS(refer to site evaluation) ca'umns <br /> 1. Depth to restricting layer= :;, inches, Z_feet tiquWc*a„ <br /> Numterof MW==LmpW LxWespacty.vah .rim duposW& <br /> 2. Depth of percolation tests = /Z inches Bedn� Wit, ppb dis"ai 11ninsidc <br /> 3. Texture .Le►,g.�-� Percolation rate /�o B o 2 i"'�' '� "u 'S°° <br /> mpi 3 V 1000 1500 2000 <br /> 5.n6 1 sat 2250 3000 <br /> 4. Land slope J % 7.s"t9 2000 3000 4000 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> -. o gpd x 0.83 sq. ft./gpd =4(p-Z Z sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') ft. <br /> 3. Len,gth of rock layer= area_width <br /> ZZ sq. ft. <br /> itd0°dlio•a.i:s� ,sz..e 0:02 . <br /> Width-/O_ft oaa®; a ao oe toe o: , ri <br /> <120mpi <10' Length-(..Z ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;&n2-Zsq. ft. x i <br /> ft. =&-ZZ cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 62-2 cu. ft. -27= ZA cu.yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;?ecu. yd. x 1.4 <br /> ton/cu. yd. =3 tons. <br /> F. ABSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is'10hanpi Percolation Rate in Gallons RadoofAbswption <br /> Minutes per Inch Soil Texture per day per width to Rack <br /> Texture_ oA (MPI) <br /> square foot Layer width <br /> Faster than 0.1 Coarse Sand 1.20 1.00 <br /> 0.1 to 5 Sand 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; 0.1 to 5 Fine sand 0.60 2.00 <br /> ppto 30 0.6 <br /> �� 6 to 15 Sandy Loam 0.79 152 <br /> . 60 Ord/ 31 to 45 Silt loam 0.550 . <br /> 00 <br /> 0 2.40 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 3. Calculate adsorption width ratio by dividing rock layer <br /> Slower than 120 Gay 0.20 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2= •4 o gpd/ft2= Z. o <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> _2 x to ft= zoft <br />