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PRESSURE DISTRIBUTION SYSTEM - Trenches <br /> All boxed rectangles must be entered,the rest will be calculated. v «k <br /> 1. Select number of perforated laterals: 03 <br /> 2. Select perforation spacing ft j F-4: NknKr,unullnwdlenn>txxo(1/4-k,chp�It�uY,nrc <br /> 1 tim k3kxcf lo gucrantee<10%cFsetw3rWt wxlalk)n <br /> 3. Since perforations should not be placed closer that 1 foot to <br /> the edge of the rock layer(see diagram), subtract 2 feet from _{(c cQ .- �_1 px:f�__4 J?-5 ku h ►s��K r, o it.a,_ <br /> the rock layer length 1 I i <br /> 25 9 td IP i ?p <br /> 63 -2 ft= 61 ft(varies) ' 3n 1 A 1" 1, 2e <br /> rock layer length ss ; ' i '' ' f <br /> d9 � 2.i <br /> Sn b 1C 14 i 22 <br /> 4 Determine the number of spaces between perforations. <br /> Divide the length(3) by perforation spacing(2)and round down to nearest whole number. <br /> Perforation spacing= 61 ft/ 3 ft= 20 spaces <br /> 5. Number of perforations is equal to one plus the number of perforation spaces(4). <br /> "Check figure E-4 to assure the number of perforations per lateral guarantees <br /> < 10%discharge variation. <br /> 20 spaces+ 1 = 21 perforations/lateral <br /> 6. A. Total number of perforations=perforations per lateral(5)times number of laterals(1). <br /> 21 perfs/lat x 3 laterals= 63 perforations <br /> 10-13 varies E-6: PertaraWcn Dsct"Ua fn UWn <br /> B. Calculate the square footage per perforation. <br /> Should be 6-10 s erf. Does not I to at-grades. prarfor nch diameter <br /> 4�P apply -9 head int;hes <br /> 1. Rock bed area=rock width(ft)x rock length(ft) (feet) ! ill 7/321/4 <br /> 10 ft x 63 ft= 630 f:2 1.00 0.18 0.42 0.5b 0.74 <br /> 2. Square foot per perforation= Rock Bed Area/number of perfs(6) <br /> 630.0 ftp / 63 perfs = 10.0 fel pert 2.0b 0.26 0.59 0.80 1.04 <br /> 5.0 0.41 0.94 1.26 1.65 <br /> 7. Determine required flow rate by multiplying the total number <br /> of perforabons(6A)by flow per perforations(see figure E-6) t,;,5•==: • ,,; I,,.t: 13 <br /> 63 perfs x0.56 gpm/perfs= 35.3 gpm <br /> 8. If laterals are connected to header pipe as shown <br /> in Figure E-1,to select minimum required lateral <br /> diameter, enter figure E-4 with perforation spacing(2)and <br /> number of perforations per lateral(5). J . <br /> Figuro E.1:Monifoid locafod al End of Sytom <br /> Select minimum diameter for perforated laterals= =inches- <br /> 9. <br /> 2 inches9. If perforated lateral system is attached to manifold pipe Figure 6-2!Mat tmoied <br /> to Me Center CO rte 8"1*m . <br /> near the center, like Figure E-2, perforated lateral length(3) <br /> and number of perforations per lateral(5)will be approximately <br /> one half of that in step 8. Using these values, select <br /> minimum diameter for perforated lateral= NA inches. 1�--- <br /> I hereby certify that I have completed this work in accordance with all applicable ordinances, rules and laws. <br /> (signature) 19e/ (license#) /`���� (date) <br />