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2001-P04115 - new septic
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2001-P04115 - new septic
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Last modified
8/22/2023 5:08:31 PM
Creation date
7/24/2019 11:32:13 AM
Metadata
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Template:
x Address Old
House Number
2995
Street Name
Watertown
Street Type
Road
Address
2995 Watertown Rd
Document Type
Septic
PIN
0411723210010
Supplemental fields
ProcessedPID
Updated
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05/20/2001 23:09 FAX 3982714 osts IM 009 <br /> PRESSURE DISTRIBUTION SYSTEM - Trenches <br /> �;eoa•�aita yab.K <br /> �auonQ n:2�. r 1C3!-an"�+wvsi°tY - - <br /> All boxed rectangles must be entered,the rest aff be calculated <br /> Paas SyxanA i.R'-S' <br /> 1. Select number of perforated laterals: 0 <br /> 2. Select perforation spacing= F-=fta►><h.�7oeaAaoklrx.7,�eiwlj44=hpw r*5-* <br /> oo k*vd to gmardm<10%d:enurgev0Kdkn <br /> 3. Since perforations should not be priced closer that 1 foot toett"kspAv <br /> the edge of the rock layer(see diagram),subtract 2 feet from 1 k-, 'AM 1 -O k <br /> i <br /> the rock layer kxvth 2.5 a 1 14 1a 26 <br /> 75 -2 ft= 73 ft ij <br /> a i 13 17 26 <br /> rock layer length 7 i, is23 <br /> 6 23 <br /> 10 14 22 <br /> 4 Determine the number of spaces between perforations. <br /> Divide the length(3)by perforation spacing(2)and round down to nearest whole number. <br /> Perforation spacing=_75 ft/ 3 ft= 25 spaces <br /> 5. Number of perforations is equal to one plus the number of perforation spaces(4). <br /> -Check figure E4 to assure the number of perinrations per lateral guarantees <br /> <10%discharge variation. <br /> 25 spaces+1 = _26 pedbrations/lateral <br /> 6. A Total number of perforations=parforations per lateral(5)thm number of laterals(1). <br /> 26 perfs/[at x_ 3_ laterals= 78 perforations _ <br /> E-6c Perfor0w 0bch0W in W0 <br /> B.Calculate the square footage per perforation. <br /> Should be 6-10 sgftlperf.Does not appy to at-grades. tread Pel fa nchl rfiumeter <br /> 1. Rock bed area=rock width(ft)r,rock length(ft) (feet) 1/rs 3116 7132 114 <br /> 10 ft X 75 -ft= 750 fe B.Oa 0.18 0,42 0.56 0.74 <br /> 2. Square foot per perforation=Rock Bed Area/number of perfs(6) <br /> 750.0 ft / 78 pen's = 9.6 ft2/pert 2Ab 026 0.59 0.80 1.04 <br /> �- 5.0 0.41 0.94 1.26 1 b5 <br /> 7. Determine required flow rate by multiplying the total number n US-.0 1.0 fax'l rof 71r,'S"'.7f 4y lwrrrm <br /> of perforations(6A)by flow per xations(see figure E-6) <br /> 78 perfs xM Jgpm/perfs= 43.7 gpm <br /> 8. if laterals are connected to header ripe as shown <br /> in Figure E-1,to select minimum required lateral <br /> diameter;enter figure E-4 with peftration spacing(2)and <br /> number of perforations per lateral(:7. <br /> Lppur•6-1-UmNed Leeolhd d End o1 lyswn _ <br /> Select minimum diameter for perforated laterals= Q Indies <br /> 9. ff perforated lateral system is alldied to manifold pipe <br /> InlMQnler d M M1on �._ �. <br /> near the center,Ike Figure E-2,petforated lateral length(3) _ <br /> and number of perforations per lateral(5)will be approximately <br /> one half of that In step 8. Using thase values,select _ �- .•�j- � - <br /> �ura+.na,�p <br /> minimum diameter for perforated lateral= 1.25 Inches. <br /> I hereby certify that I have completed this work in accordance with all applicable ordinances,rules and laws. <br /> ,, (signature) l 9�� (license#) <br />
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