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2011-00401 - new septic
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2011-00401 - new septic
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Last modified
8/22/2023 5:08:19 PM
Creation date
7/24/2019 10:36:51 AM
Metadata
Fields
Template:
x Address Old
House Number
2985
Street Name
Watertown
Street Type
Road
Address
2985 Watertown Rd
Document Type
Septic
PIN
0411723210001
Supplemental fields
ProcessedPID
Updated
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OSTP Pressure Distribution <br /> LTNIVEI2SIT1' <br /> P0111,1600 Design Worksheet of IV11NNESOTli <br /> (Ill ul %\CJc'11�jr <br /> r-- <br /> i. Select;qumber of Perforated Laterals in system/zone: ® m <br /> Geolr. e <br /> , U61 a zi USI.sDVRk:�C�G�L J���iL`Ol: I:linnnun )�:vGiO 1Cr_- 0 4 <br /> (_feet is minimum and 3 feet is maximum spacing) Prlorallons spacd apan <br /> ._ �yP4li C67✓Or, <br /> _. Select Perforation Spacing: 1 �ft � Al <br /> --' <br /> `c �i+c"oo�'� o l�.i c: or✓urr gr'y ho` <br /> of luck wDoOiD,�U�DoUvU��rnCC,..�_rvl <br /> Select Perforation Diameter Size / �'✓' inch Ierforationiizul9: <br /> V010r3110n spaeuul:2'10 <br /> Length of Laterals =Media Bed Length - 2 Feet. Perforation can not be closer then 1 foot from edge. v 11.05.31 <br /> r-=li - 2ft = ft <br /> �— <br /> 5. Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces ft ft = ,�Spaces <br /> I <br /> o. Number of Perforations per Lateral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Lateral = / Spaces + 1 = Perfs. Per Lateral <br /> I <br /> Check table below to verify the number of perforations per lateral guarantees less than a 10%discharge variation. The value is <br /> double if the a center manifold is used. <br /> I <br /> �- Total Number of Perforations equals the Number of Perforations per Lateral (Line 6) multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> Pert. Per Lateral X Number of Pert. Laterals = Total Number of Perf. <br /> o. Calculate the Square Feet per Perforation. Recommended value is 4-10 ft per perforation. (OPFII <br /> PEfiGra uGn 0iame Wr ------- <br /> Does not apply to At Grades Bend Ill) <br /> Bed Area = Bed Width (ft)X Bed Length (ft) o— a o.,, V34 <br /> 1.5 0.22 0.51 0 6 0.9 <br /> ft X ft = ftz a o` 0.26 <br /> osv u.ao - <br /> 2.5 0.29 O.a5 0.69 1.17 <br /> 3.0 0.32 0,72 0,98 1.'_8 <br /> .Square Foot per Perforation =Bed Area divided by the Total Number of Perforations (Line 7). a.o 0.37 o.s3 ,— 1 4Y_ <br /> 5.0` O.i1 U.93 l.�0 1 65 <br /> z 2 1 1wc u..eun.��—0,31115 1-1, <br /> [� lft - perforations = ft /perforations <br /> 9, Select Minimum Average Head: 2 feet lllIfta(oWl'I111I1 :d <br /> a � f' In /1•. <br /> ft 1181 l 1 a I. np pea—to., <br /> 5 ltct 41n2f 2.[abllsnm2n(anJ:vST' u:1:51n:n <br /> p.norzuon: <br /> 10. Select Perforation Discharge (GPM)based on Table III: GPM per Perforation - -- <br /> Determine required Flow Rate by multiplying the Total Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br /> L1 11 <br /> 1_1Perforations X GPM per Perforation = GPM <br />
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