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2011-00401 - new septic
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2011-00401 - new septic
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Last modified
8/22/2023 5:08:19 PM
Creation date
7/24/2019 10:36:51 AM
Metadata
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Template:
x Address Old
House Number
2985
Street Name
Watertown
Street Type
Road
Address
2985 Watertown Rd
Document Type
Septic
PIN
0411723210001
Supplemental fields
ProcessedPID
Updated
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OSTP Pressure Distribution <br /> `linnt ota PollutionDesigQn Worksheet UNIVERSITYntuoI Ag,�ncy S OF MINNESOTA <br /> i. Select Number of Perforated Laterals in system/zone: +�y _ �e�tr life <br /> `�"` D�CUJA J0�9UAOiawmp)..� iU�.� IVlinimum�Crip��%e �l5vODi%rUU: <br /> (2 feet is minimum and 3 feet is maximum spacing) perlDralions spaced 9'apart ul mck= � `z�.<�c-.`U�.c <br /> ?. Select Perforation Spacing ft <br /> dcd C6o <br /> Uo�'Uoc�iU�_O�e1G�(�r0�,� 0c�Do� 9••of rock wU�O®p6��aD0.7nUBOvOP�r/U� ivo�� <br /> Uo`� o"�o `�So`�ro 6��Yo U000"" )Jo`do�co"`%O�o�o <br /> 3. Select Perforation Diameter Size _ � inch <br /> Perforation sizing, 1" 10 <br /> Pedoia(ion spoon::2'to 3' <br /> 4. Length of Laterals =Media Bed Length -2 Feet. Perforation can not be closer then 1 foot from edge. v 11.05.31 <br /> `-j - 2ft = .? ft <br /> 5. Determine the Number of Perforation Spaces. Divide the Length of Laterals (Line 4)by the Perforation Spacing (Line 2)and <br /> round down to the nearest whole number. <br /> Number of Perforation Spaces = 1 ft ft = ®Spaces <br /> 6. Number of Perforations per Lateral is equal to 1.0 plus the Number of Perforation Spaces (Line 5). <br /> Perforations Per Lateral = / G Spaces + V = 1 r ---7Perfs. Per Lateral <br /> Check table below to verify the number of perforations per lateral guarantees less than a 10%discharge variation. The value is <br /> double if the a center manifold is used. <br /> T <br /> Y.) <br /> 7. Total Number of Perforations equals the Number of Perforations per Lateral (Line 6)multiplied by the Number of <br /> Perforated Laterals (Line 1). <br /> /�; Perf. Per Lateral X Number of Perf. Laterals = Total Number of Perf. <br /> 8. Calculate the Square Feet per Perforation. Recommended value is 4-10 ft 2 per perforation. Perforation Discharce(GPM) <br /> Does not apply to At-Grades Perfora[ion Diame[e <br /> Head(ft) <br /> Bed Area = Bed Width (ft)X Bed Length (ft) ° <br /> 0.18 O.4'1 0.56 0.74 <br /> `� <br /> 1.5 0.22 0.51 0.69 <br /> ✓✓J 0.9 <br /> -J ft X � K ft = '✓`.' / ) <br /> ft, 20° 0.25 0.59 0.80 1.04 <br /> 0.J '_>.5 0.29 0.65 0.69 1.17 <br /> 3.0 0.32 0.721-0.98 1.28 <br /> Square Foot per Perforation =Bed Area divided by the Total Number of Perforations (Line 7). 4.0 0.37 0.83 1.13 1.47 <br /> 5.0` 0.41 0.93 1.26 1.65 <br /> ft perforations ftZ ellis.- <br /> [,3/16 iich(,,1/4h/perforations <br /> P=rtoiarwn, <br /> D>:ellinj r.i1h i cinch perioiati�ns - <br /> 9. Select Minimum Average Head: ft 2 fz Uther atawishment an "f; irh;i to <br /> inch to V4 inch parforaticros <br /> S fent t�tllzr Y.tahli5hmcnlS and NfiTl.vi[h I•S iiKh <br /> 10. Select Perforation Discharge (GPM)based on Table III: GPM per Perforation Penor t on, <br /> 11• Determine required Flow Rate by multiplying the Total Number of Perforations (Line 7)by the Perforation Discharge (Line 10). <br /> ®PerforationsX GPM per Perforation = GPM <br />
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