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1996-008606 - new septic system
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2760 Watertown Road - 33-118-23-43-0020
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1996-008606 - new septic system
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Last modified
8/22/2023 4:52:17 PM
Creation date
7/24/2019 8:20:19 AM
Metadata
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Template:
x Address Old
House Number
2760
Street Name
Watertown
Street Type
Road
Address
2760 Watertown Road
Document Type
Septic
PIN
3311823430020
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Esdnmed Sewage flow in Gallons pw Day(gpd) <br /> Estimated r)S(D gpd Number ` <br /> or measured x 1.5 = gpd. �e� ape I II Type III Typo IV <br /> 2 300 225 180 cos <br /> 3 450 300 218 of <br /> B. SEPTIC TANK LIQUID VOLUMES 4 600 37s 256 .:. <br /> -1�S 0 4T -1 co() gallons 6 9 0 `sats50 332 � <br /> 7 1050 600 370 C= <br /> 8 1200 1 675 406 <br /> C. SOILS(refer to site evaluation) Numbw rf <br /> 1. Depth to restricting layer= ►y -Tb inches s CA,o,rf srr <br /> 2. Depth of percolation tests = 1 a" inches `"°"° `'°'"' <br /> 3. Percolation rate L4,S mpi 2s alb 17500 1.1 I. S <br /> 4. Land slope 3 % 7 or s 2.� 300 <br /> over 9 See fig.C-6 (x 1.5) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer.A x 0.83 = <br /> � <br /> �_gpdx0.83sq. ft./gpd = !,a� sq. ft.-�1�°>0=��sy° <br /> 2. Select width of rock layer(10 feet or less) <br /> 3. Length of rock layer= area 1 width= Rock Bed <br /> �u y sq. ft. o <br /> r.r.rw•r•r•�•f•r r•r•r•f•r•r•�• idth 510 ft. <br /> 1�'tif�•ti��f�:wSf�`��1��w�tir�fS?ti <br /> E. ROCK VOLUME �- Length -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock <br /> I,y4 sq.ft. x /u_< ft. = 0 1�4 cu. ft. <br /> 2. Divide cu.ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> r))g cu.ft. 27= '.)n cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> ',') cu.yd.x 1.4 ton/cu. yd. = -Z �'tons. <br /> F. ADSORPTION WIDTH Absozpfion Mdth SzLrngr ble <br /> 1. Percolation rate in top 12 inches of soil is Li,-s's mpi Percolation Rabe °•a"• """'of <br /> Soil Texture �r <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse sand 1.20 1.00 <br /> gpd/ft2 0.1 toy Sand 120 1.00 <br /> 0.1 to 5 Fine Sand- 0.60 2.00 <br /> 6 to 15 sandy Loam 0.79 1-52 <br /> 3. Calculate adsorption width ratio b dividing rock layer 16 to 45 Loam OM 2.40 <br /> rP � Y g Y 31 to 45 silt Loam OM 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 Cla Loam 0.45 2.67 <br /> 1.20 gpd/ft2i •Ll gpd/ft2= a.L� Slowertthan 120 Clay 024 5_00 <br /> ••Soil laving 50%or mora of fine or very fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> v,�,q_x /0 ft=aL.r) ft <br /> J <br />
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