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E-19 <br /> MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> j A. FLOW D-7 <br /> Estimated gpd IiA1iR(see pages D-7 or I-3,4,5) BIM FLOW a..�..,.�, <br /> T7P!aF..sw.ua <br /> or measured gpd. °m"°°'" t n Ix <br /> a 300 m too "I <br /> 3 400 300 210 <br /> 4 .00 370 = 7yM <br /> B. SEPTIC TANK LIQUID VOLUMES5 M 450 2M <br /> • .00 on 332 Rz. <br /> 7 1000 ' .00 370 <br /> gallons (see pages C-3 or C-5) Iwo °7° <br /> C-3 <br /> C. SOILS (refer to site evaluation <br /> SEPTIC TANK CAPACITIES, IN OALLONB <br /> 1. Depth to restricting layer= inches �.. ...olle `.1131111"PAO" <br /> inches <br /> 1.10M10M CAPAor. 01.PMAL <br /> 2. Depth of percolation tests = inches a OR LM 7.. 11=5 <br /> 3. Percolation rate mpi _ +N /N. <br /> Sass <br /> 4. Land slope % QI1. <br /> a... 3000 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> gpd x 0.83 sq.ft./gpd = sq. ft. <br /> 2. Select width of rock layer(10 feet or less) <br /> 3. Length of rock layer= area+width= <br /> sq.ft.+ ft. = ft. Rock Bed <br /> ' J•r•r•r•r•r•J'f';•r•r�•J'•�•r <br /> ti•ti•ti•ti ti•ti•ti•ti•ti ti•ti•ti•ti•ti•ti• <br /> J•J•r•J•J•J•J•J•�•J•J•J•J•J•J <br /> ti•ti•ti•ti•ti•ti•ti•ti•ti ti.ti.ti.ti.ti.ti. dth S10ft <br /> r•r•r•J•J•J•r.J•�•J•J•J•r•r.r <br /> ti•ti <br /> ti. •ti•ti•ti.ti.ti•ti ti•ti•ti•ti•ti•ti• <br /> •J•J.J.r•J•J•J•J•J•J•J•J•r•r•r <br /> E. ROCK VOLUME Length --' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> sq: ft. x ft. = cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> cu. ft. +27= cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> cu. yd. x 1.4 ton/cu. yd. = tons. <br /> t <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is mpi E-16 <br /> 2. Select allowable soil loading rate from table on page E-16; •�WA01111111RAMd•01.•1010• • <br /> 8Pd/ft2 ..�.... ,...�....... _ <br /> ' __ <br /> 3. Calculate adsorption width ratio by dividing rock layer SIA """ `"'r"""" <br /> .e• s I ..w 43-0210 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; ; M L"I ` <br /> 1.20 gpd/ft2+ 8Pd/ft2= ..7: .40 <br /> .1 •IH .... ..7. ..N .... <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> -X-ft= ft <br />