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septic info including 2002 design
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2590 Watertown Road - 33-118-23-44-0042
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septic info including 2002 design
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Last modified
8/22/2023 4:53:22 PM
Creation date
7/22/2019 9:08:26 AM
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x Address Old
House Number
2590
Street Name
Watertown
Street Type
Road
Address
2590 Watertown Road
Document Type
Septic
PIN
3311823440042
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW �Sewage Flo"in canon per day <br /> Estimated d gpd ;7ya1 Yypen Type 7Ype <br /> or measured x 1.5 = - gpd. <br /> 2 300 225 180 60% <br /> B. SEPTIC TANK LIQUID VOLUMES 3 600 Sao 216 g,, <br /> a 6U0 375 256 <br /> 5 750 45D 2% gn <br /> 1_ z to 4- )-)ov o gallons �s 1- M So �,I 70 vti'P -�iAaa�. 6 i o 52560D 32 TQ L <br /> 8 1200 675 408 M <br /> eolumns <br /> C. SOILS (refer to site evaluation <br /> 1. Depth to restricting layer= ��-ao inches - feet LArAd"> <br /> ,� � -gin . <br /> 2. Depth of percolation tests= ►�'' inches lift is" <br /> 3. Texture cLA�{ N-on nn Percolation rate 31-'► mpi 23w' 1� i� XW <br /> S,w n ism 2250 3000 <br /> 4. Land slope 14 % I7.a ow V 2000 3000 JIM <br /> D. ROCK LAYER.DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> I)SC) gpd x 0.83 sq. ft./gpd = (,aZ sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /0 ft. <br /> 3. Length of rock layer= area+width= � •- -�-- <br /> �a a s ft. + /Q _ft. _ tel ft. R'33� D. <br /> 'C t <br /> z <br /> q• d�t; r <br /> Width I o ft <br /> <120mpi <10' Length--k3-ft <br /> >120mpi <5' <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;S¢a.3 sq. ft. x LLL <br /> ft. =54a.cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> �cu.ft. +27 =a4 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; ;L9 cu. yd. x 1.4 <br /> ton/cu. yd. _ i L) tons. <br /> F. ABSORPTION WIDTH ,UoMdon Width std Tabk <br /> 1. Percolation rate in top 12 inches of soil is 31.0j mpi Poe ieoen wm ie "am Rado of+spoon <br /> Minoan Ineb Soil Tmare per day pa widtb to Rock <br /> Texture GL-� k-oA-v, cr+�i .tee rot L.Y. Ab <br /> Fuer duo 0.1 Coarse Siad 1.20 1.00 <br /> 0.1to 5 Siad 130 1.00 <br /> 2. Select allowable soil loading rate from table; 0.1 to$ Fine sena 0.60 2.00 <br /> O 6 to 15 Sandy Loam 0.79 1.52 <br /> y j gpd/ft2 16.30 Loam 0.60 2.00 <br /> 31 to 43 Sib Loam 030 2.40 <br /> 46 to 60 Clay Lrnm 0.43 2.67 <br /> 60 w 120 clay034 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer Sl-d-Ito city 0.20 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2+ - 4,5- gpd/ftz= . 2.6/2 <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> ��X to ft= ;Z(,.,) ft <br />
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