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1996-008313 - new septic system
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2325 Watertown Road - 03-117-23-22-0015
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1996-008313 - new septic system
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Last modified
8/22/2023 4:34:37 PM
Creation date
7/17/2019 10:19:47 AM
Metadata
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Template:
x Address Old
House Number
2325
Street Name
Watertown
Street Type
Road
Address
2325 Watertown Rd
Document Type
Septic
PIN
0311723220015
Supplemental fields
ProcessedPID
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ATGRADE DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) F,6..ed Sewage Flow in Gallons per Day(gpd) <br /> Number <br /> Of Type I Type II Type III Type IV <br /> A. FLOW Bedrooms <br /> s s0fEstimated o gpd g <br /> s �° 7aormeasured x1.5 = - gpd. d. <br /> "!ss29 <br /> 6 900 525 332 <br /> 7 1050 600 370 ®, <br /> B. SEPTIC TANK LIQUID VOLUMES 1 g 1 1200 675 408 <br /> ),-)00(-) gallons Number <br /> Minimum Minimum <br /> c TWt <br /> C. SOILS (refer to site evaluation) Bed°�ms C GPuri with <br /> nom`► <br /> 1. Depth to restricting layer =-I(, -,v L) inches (8".1 <br /> 2. Depth of percolation tests = )a- `' inches 2 or less 750 1,125 <br /> 3. Percolation rate )0 - 7, mpi 3 or 6 1.0001-SW 1_W <br /> 4. Absorption Ratio gpd/fF 7 or s 2.000 3,000 <br /> 5. Linear Loading Rate: 8 6 ,4 3 2 gpd/ft over See fig.C-6 (X 1s) <br /> 6. Land slope % Absorption width SizingTable <br /> D. ROCK WIDTH percolation RateCa <br /> Ratind <br /> Minutes per inch Soil TeXtUre �,y e. �yb <br /> 1. Percolation rate in top 12 inches of soil is i u.` mpi (Mpi) `"` 'b" <br /> 2. Select allowable soil loadin rate from table; Faster than 0.1 Coarse Sand 1.20 1.00 <br /> g 0.1 to 5 Sand 1.20 1.00 <br /> (p!� gp d/f tz 0.1 to 5 Fine Sand- 0.60 200 <br /> 6 to 15nd Loam 079 1.52 <br /> 3. Calculate adsorption width of the rock by dividing 16 to 30 Loyam 0.60~ 2.00 <br /> 31 to 45 Silt Loam `(Y.50: 2_40 <br /> rock layer loading rate by allowable soil loading rate; 46 to 60 ClaLoam 0.45 267 <br /> Hgpd/ft t <br /> Slower than 120 Clay t l.y gpd/ftz= _eft• ` ' : 61 Clay o.2a 5_00 <br /> -Soil having 50%or mote of fine or very fine sand. <br /> E. SYSTEM SIZE MPI Soil Texture Other characteristics Linear LatdingRate <br /> in the intita 48" (gpd/ft) <br /> a. The Height of the System is_�feet(2') Fasterthan O.1 Coarse Sand For the entire depth 6 <br /> b. Enter table with landslope No Banding- g <br /> andupslope dike ratio. 0.1 to 5 Sand Layers with no Mottles 4 <br /> Select dike multiplier of D a 5 to O.1 Layers with Mottles 2 <br /> Fine�a., d - <br /> c. Multiply upslope dike multiplier by - - No change in texture 6 <br /> heigpht to find upslope dike width: Layers ofotlternQures 4 <br /> C p t" 6:o IS Sandy Loam <br /> 2 ft x `).a2 = (, feet 16 to 30 Loam <br /> d. Enter table with landslope and Nod+ofothe textur <br /> 31 to 45 Silt Loam <br /> do«-nslope dike ratio. Layenefothertextutea 3 <br /> _! 46 to G7 Clay Loam <br /> Select dike multiplier of 4 . 60 to 120 Bdk Clay For the entire depth <br /> e. Multiply downslope dike multiplier by "2O �` g 2 <br /> Bedrock encountered in the borin <br /> height to get downslope dike width: <br /> ft x 9V_ a feet <br /> f. The System width is the sum of upslope dike width plus downslope dike width; <br /> !_ft+)aft = l %Z feet <br /> g.The rock layer length is the flow divided by LLR _H_�Q i !d_ = 113 feet <br /> 1. Total length is the sum of upslope dike width plus rock la".'er length plus <br /> upslope dike width: '(e-ft+ 1);, ft + , ft= 1 a Jfeet <br /> F. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;aft-L aft-Lsq. ft.x L ft.:2 = 3c7 1,cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu.yd. to get cubic yards;7&k cu. ft. -27= I -C,_cu.yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; t S'' cu.yd. x'1.4 = tons. <br />
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