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2003-P06324 - new septic
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2003-P06324 - new septic
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Last modified
8/22/2023 4:30:31 PM
Creation date
7/3/2019 1:28:42 PM
Metadata
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Template:
x Address Old
House Number
465
Street Name
Turnham
Street Type
Road
Address
465 Turnham Road
Document Type
Septic
PIN
3111823240013
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Fsunwtd Sewage Flows In Gttlont pet day <br /> Estimated �� gpd 6���o Munba Type rnenl typem '1 <br /> or measured x 1.5 = gpd. kwIn " <br /> 2 3W 22.5 Ito• 6M <br /> 19 <br /> B. SEPTIC TANK LIQUID VOLUMES 4 " 3305 2 <br /> 2 2-3'b gallons .2 r.-A 6 � su iii �In <br /> 7 1050 Im 370 Type o <br /> a <br /> O <br /> 8 1200 675 408 lit <br /> C. SOILS (refer to site evaluation) co1°nm <br /> 1. Depth to restricting layer _ i /L _ inches feet L-r-..0-r <br /> 2. Depth of percolation tests = 12 irlcllc'; s....„a,p..l snl..w <br /> t S0(1 <br /> 3. Texture �bG .,, Percolation rate 1 -7o jilpilo„ <br /> 1••• 1 uo »30 )000 <br /> 4. Land slope 5 '% 7.a,.. ,n., >aD <br /> D. ROCK LAYER DIMENSIONS <br /> I. Multiply flow rate by 0.83 to obtain required irea of rock layer: A x 0.83 = <br /> 2f-e _ gpd x U.i3:.1 sll. f t./gpd = (o2d sd. f t. <br /> 2. Select width of rock layer (inax 10' if <120 111pi max 5) = eD ft. <br /> 3. Length of rock layer = arca - width <br /> lo?-c7 5q,.ft. /D ft. _ �2 _ ft. <br /> •...•.,J`U p.VpU ltt ID ,ltJ t.'�i;.0` ^^"'. <br /> Width ft pb <br /> <120ttlpi <10, Length .ft <br /> ROCK VOLUME' >120u1pi <5' <br /> 1. Multiply rock arca by rock depth to get cubic feet of rock; 4120 Sq. ft. x <br /> ft. = re20 cu. f t. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> (,20 cu. ft. 27 = z 3 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to Fact weight of rock in tons; �3 cu. yd. x 1.4 <br /> ton/ell. yd. = 2.2 t(1n.. <br /> F. ABSORPTION WIDTH Absorption WI41tb Stzhit'fable <br /> I. Percolation rate in top 12 iilchts of soil is/G 3a t111�i I'mej-60,R-„•;n Gallo" RA6co(Aliva,pia, <br /> Texture (6 G mss.- Mieutm pep Inch Soil 7eaeut o.,Aa P- -;d1A to Pock <br /> l�sp11 aquMe t«w layer W1dlh <br /> raut,thm 0 1 Coale Sand 1.10 1.00 <br /> 0 I to s SWA 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; 0 los rntSam 060 200 <br /> &In 1 s Sandy Loam 079 11.32 <br /> g p d/f t 2 16 l0 30 loam 060 2.00 <br /> 31to 43 Sill Loam 030 2,40 <br /> 46%060 clay Loam 045 2.67 <br /> 6010 12o Clay 0 2A 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer than 120 clay 0:0 600 <br /> loading rate of 1.20 gpd/ft'. by allow,ihic' lc,,idint, rate; <br /> 1.20 gi3d;1,2, . � 1,1'd/ft' _ • �.o <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> 2.in x /0 ft = 20 ft <br />
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