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• E-19 <br /> ' 6 MOUND DESIGN WORKSHEET <br /> • (For Flows up to 1200 gpd) <br /> A. FLOW D-7 <br /> Estimated 4/ gpd (seepages D-7 or I-3,4,5) ani"TED SEVANE <br /> rt0"1N 6"UMS M06' <br /> TYPE.F RnKNDC6 <br /> • <br /> or measured gpd. a I = <br /> 2 300 220 16a 60% <br /> 3 400 300 216 at <br /> 4 600 370 2961 <br /> B. SEPTIC T LIQUID VOLUMES a 9W .650 = "M; <br /> gallons (see pages C-3 or C-5) 100° 600 "° <br /> s 1200 6i3 406 <br /> C-3 <br /> C. SOILS (refer to site evaluation) <br /> SSPTIC TANK CAPAQ'n9% IN GALLONS <br /> GWAAWY <br /> 1. Depth to restricting layer= inches NI6i•IOP 14"•NS ` <br /> 666100600 Muss C"Au" 016P06u <br /> 2. Depth of percolation tests = inches 2,116= t6. ,,16 <br /> 3. Percolation rate mpi6«4 1N. s66 <br /> .011. ,400 6166 <br /> 4. Land slope % <br /> 1666 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> gpd x 0.83 sq.ft./gpd =, sq. ft. <br /> 2. Select width of rock layer(10 feet or less) <br /> 3. Length of rock layer= area width = <br /> sq. ft. + ��ft. _ _ft. Rock Bed <br /> J•J•J.J•J•J•J•J J•J•J•J•J•J•J <br /> ti•tiK•ti•ti•ti•ti•ti•ti•ti•4..ti•ti•tiK• <br /> •J•J•J•J.J•J•J•J•J•J•J•J•J•J•J dth 510 ft <br /> ti•tiKK•ti•ti•ti•t•ti•4•ti•ti•�•ti•ti• <br /> J•HJ•J.J•J•J•J J•J•J•J•J•J•J <br /> ti•ti.t.ti•tiK•ti•ti•tiK•ti•ti•ti•ti.ti. <br /> •J•J•J•J•J•J•J•J•J•J•J•J•J•J•J <br /> E. ROCK VOLUME Length --+ <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> Multiply <br /> ft. x . �cu. ft. <br /> i <br /> 2. Divide cu. ft. by 27 cu. ft./cu. vd. to get cubic yards; <br /> M cu. ft. j-27= cu. yd. <br /> 3. MuTW-Ccu- <br /> ubic yards by 1.4 to get weightof rock in tons; <br /> yd. x 1.4 ton/cu. yd. = ons. <br /> I <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is mpi E-16 <br /> 2. Select allowable soil loading rate from table on page E-16; N{06/661►666M66.100P 666666611016106 <br /> gpd/ft2 <br /> 3. Calculate adsorption width ratio by dividing rock layer *V. "'4M µ" -par ""6...1.1 <br /> .2 <br /> loading rasp of 1.20 �gpby allowable s loading rate; 31 •10 0.» 0.» ,... ..» <br /> 71 •16 M. 0.» <br /> 1.20 d/ft2+ d/ft2= • S 0.24 0.66 ..» M" <br /> Check this value on page E-16. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required ads o �ti width; <br /> - u, xft= 20 ft <br />