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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW E11maw4 Sewap Flows ie C Ilk"pw day <br /> Estimated oc) gpd 4 (s•,al <br /> or measured x 1.5 = gpd. a I Type I Z pe u Type m 7* <br /> B. SEPTIC TANK LIQUID VOL S �} 3 � 3W iu <br /> VOL <br /> a boo ns 294 .,.., <br /> �- /006 gallons 6 700 as0 <br /> 6 900 525332 332 +�•� <br /> 7 1030 600 370 to <br /> .a.... <br /> C. SOILS (refer to site evaluation) E I:00 673 403 <br /> 1. Depth to restricting layer = 2f-1-0-j2; inches sq-y-carwAlm•PA- <br /> N�vav d Mu...wiN t•td 0ie.a.y.•. <br /> 2 Depth of percolation tests = /�-o inches ...,�. � <br /> 3. Percolation rate 50. 7 mpi =3 a * <br /> 4. Land slope //,o % ,';', n , <br /> H <br /> D. ROCK LAYER DIM�'SIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = _ Z <br /> gpd x 0.83 sq. ft./gpd = 500 sq. ft. * 109 C) - 5 J <br /> 2. Select width of rock layer (10 feet or less) __ n _ft. <br /> 3. Length of rock layer = area+ width = Reck Bed <br /> U sq. ft. + to ft. = S ft. % <br /> ,....\ �............., . \ \..,....,..... �Q <br /> . .% %•r•:%•:%•!%•r•/•r•r•�•r•r•/ .%. <br /> \/�/•!•!•!•r /•r•/ I•!•I•/•r•/•!• <br /> ♦.\.\.•..\.\.\.�•\�:i•�•\•\•\• kith S1 ft. <br /> I•r•I•r•r•J /•/•/ !• I•/ /•I•ItI <br /> E. ROCK VOLUME f--- length --+ <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; 5S <br /> 530 sq. ft. x , ) ft. = 55f cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 55+x' cu. ft. +27- 0-q cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> c�cu. yd. x 1.4 ton/cu. yd. _-M tons. f 01 <br /> F. ADSORPTION WIDTH 6C, -/ ZL Absorption Witch Sizing Table <br /> Fereolacion R Galbm Karroo <br /> 1. Percolation rate in top 12 inches of soil is, mpi ;�.tlnuteaP SoilUAIIAra 1P.,d y1. Atwosyr- <br /> McA(MPl) square tow b Rock 1� <br /> %r ft <br /> 2 Select allowable soil loading rate from table; Fant®than 0.1• coarse Sam -. _. <br /> Zy0.1 to 3 Sand 1.70 1.00 <br /> gpd/f t2 0.1 to 3•• Fine Sand•• 0.60 t00 <br /> 6 to 13 Sandy Loom 0.79 I.32 <br /> 16 to 30 Lore 0.60 100 <br /> 31 to-93 Silt Loam 0.30 i40 <br /> 3. Calculate adsorption width ratio by dividing rock layer 46 to 60 a � mss_. 2.67 <br /> loading r9te of 1.20 gpd/ft2 by allowable soil loading rate, s crftn - <br /> 1.20 gpd/f6+0,zy gpd1fe <br /> • :Soil too eoane for installation of a <br /> standard system: <br /> See 7030.0170 Sulbp W.3.ps3e 36. <br /> 4. Multiply adsorption yvidth ratio by rock layer width to get •• ,Satlhavins sosottttotsarfMesand <br /> plus Very Ing san& <br /> required ads? tion width; Sail too heavy for installation of a <br /> `n standard system. <br /> .Oo x /o ft ft see 7090.0210 Subp S.A.pop 33. <br />