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MOUND DESIGN WORKSHEET �\,,,3o, O°QD <br /> • (For Flows up to 1200 gpd) <br /> A. FLOW•OW Eaun mil Sawap Flows in Gallom pet day <br /> gpd9clpol <br /> Estimated to°y <br /> or measured x 1.5 = gpd, v f type 1 Type 11 Type M <br /> Bedrooms <br /> t 2 300 223 110 <br /> B. SEPTIC TANK LIQUID VOLUMES 700216 .o. <br /> ns 236 "°" <br /> - /oa e) gallons a 332 730 430 rr` <br /> 900 32s ssz <br /> 7 1030 600 310 � <br /> 1 1 1200 677 401 .ww. <br /> C. SOILS (refer to site evaluation) •• <br /> ho so- <br /> 1. Depth to restricting layer= cZ S`'$ inches ''"''"�''AJ U <br /> 2 Depth of percolation tests s ""°"` `�"��'"~"°`.'MW <br /> la inches •«•••• �. r.�..•Y-r <br /> 3. Percolation rate W�r9 mpi 1. <br /> 4. Land slope ro r 0 9ro ?Aa ;� � <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = 6bO'� z. <br /> to°6 gpd x 0.83 sq. ft./gpd =d sq. ft. = <br /> 2. Select width of rock layer(10 feet or less) ft. <br /> 3. Length of rock layer ae area+width as Rock Bed <br /> It••rI••tr••II••�•^�•t••t••♦•tI.I••I••��•♦.;500 sq. t.+ a ft. MI!.,•• Idth�I.•••. <br /> to <br /> t•t•I•I•I•!•t•I.I f•I•I•I•I•I•/• <br /> NN•I•HHI•�•I M•HHI•HI•I•t• <br /> E. ROCK VOLUME I Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; S o <br /> Sao sq. ft. x ! ft. = Sa cu. ft. , <br /> 2. Divide Cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 16°o cu. ft. +27 a_[7 .cu. yd. <br /> . 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> _LL cu. yd. x 1.4 ton/cu. yd. =6 _ tons. <br /> Absorptla Miltb Sinn`Tabie <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is`-�-� mpi Percalldon litre c.uy p Ratio or <br /> in Minwa per Soil Tt state per day per Abaptioe+ndN <br /> Uixa. y.&-6o m P( «A V Iw A rvy\ Z pt��5 90(L ineA(MPl) agave raa w-Width y« <br /> 2. Select allowable soil loading rate from table; Pssw Mae 0.1 caer,..;end - <br /> 0.1 u13 s••�1 1.20 1.00 <br /> 6.,V6" gpd/ft= 0.1103•• FlMS.,d•• .0.60 Loo <br /> 610 13 Send) amt 0.79 1.13 <br /> • 16�a'�30 (.w a 0.60 2.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer •6���b60 J 'a ' <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; s1 athan c:.r -- -- <br /> 1.20 d/Et=+ t7.Y� d/f{2= • installation ar. <br /> gpd/ gpd/ Soil too coos.d.. <br /> . fI:dN'd 1y stem. <br /> Sa 7010.0170 3•obp 2.0.3.pals 26. <br /> .4. Multiply adsorption width ratio by rock layer width to get •• p� ��ry�M � �_ <br /> required adsorption width; Soil too nTZIOS.bpS. <br /> )for inusltetlo0 of• <br /> •••su" a"7 x w f t = ft see 7o/o. A.p.1d 37. <br />