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E140 PERFCRATION CF 4 PEAFORAT90 LATERAL <br /> PRESSURE DISTRIBUTT0N SYSTEM <br /> Taoew t. <br /> I. Select number of perforated laterals 3 <br /> '.•La1w of Geaaslea RsWa lar fW <br /> .• Law"Sana L"W ha er ww"Wwoa <br /> 2. Select perforation spacing = feet "'�' <br /> ��— , 110b" <br /> rera/t�TT«ll.auaaal� <br /> 3. Since perforations should not be placed closer than I ft. to ;horgin F1N.a« : am 'tom `°� <br /> the edge of the rock layer(see diagram), subtract 2 ft. from Pwloralaaa l.�at« <br /> Y g of <br /> clala sane �r e.n«w el Larval <br /> the rock layer length. / <br /> �J/� orlyaa Sell PM-06"Y Scarltted <br /> ---� 3 feet. <br /> ft. = S - .aw.PIa«�a saM <br /> Rock layer length TABLE OF PERFORATION DISCHARCES IN CM <br /> 4. Determine the number of spaces between perforations. Head Perforation diarneter(inches) <br /> Divide the length above by perforation spacing and round tea t/, <br /> down to nearest whole number. 0.56 0.73 <br /> 1.5 0.69 0.90 <br /> Length perf. spacing ft.+-: ft. = t 7 spaces is <br /> a� �:i <br /> (3) (2) 3.0 0.98 1=8 <br /> S. Number of perforations is equal to one plus thr number of 5.o 1.26 1.65 <br /> perforation spaces . <br /> aL'se 1.0 foot of head for residential systems. <br /> buss 20 feet of head for other establishments <br /> spaces + 1 =_�,perforations/lateral <br /> ..W drt <br /> 6. Multiply perforations per lateral by number of laterals to --1— 1.2.5inch 1 J inch - 2.0 inch <br /> get total number of perforations. 2s 14 28 <br /> 3. 13 `11 ' 26 <br /> _3 r$ —3 3� 12 16 25 <br /> b`� perforations. 4.0 11 15 23 <br /> laurel a x Pads/Imeral= 5.0 10 1; 22 <br /> 7. Determine required flow rate by multiplying <br /> number of perforations by flow per perforation <br /> 5-4 0',2`f = q gpm. W.a.a <br /> patsx 81Ziwf <br /> 8. If laterals are connected to header pipe as shown on upper <br /> example, to select minimum required lateral diameter; enter ✓��? <br /> l�r.�rs <br /> table with perforation spacing and number of perforations <br /> per lateral. Select minimum diameter for <br /> perforated lateral = inches. <br /> s <br /> 9. If perforated lateral system is attached to manifold pipe near =` <br /> the center, lower diagram, perforated lateral length and " Mr,="'—' <br /> number of perforations per lateral will be approximately one / �, "'' <br /> half of that in step8. Using these values, select minimum „�''� ��° , <br /> diameter for perforated lateral = 1l2 inches. �.��''�� Z <br /> �6,J <br />