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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) ,La T*7 B,,K / <br /> A. FLOW Esttmau:tl Scwage Flow in Gailem pa day <br /> Estimated fn o o gpd C. �'�' � ��'��^^� (c, ) <br /> .un,osr <br /> of Type l Typa a TyPr III TYO. <br /> or measured x 1.5 = gpd. Qomn. IV <br /> 2 300 225 110 <br /> B. SEPTIC TANK LIQUID VOLUMES 30A 2:6 <br /> 600 373 2S6 <br /> 2 - Ano gallons O gc,o.JcCc,pt' .yo 294 .w.. <br /> 6 900 323 332 <br /> 71050 000 370 tp <br /> 8 1200 677 40 .ay.•e <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer=, 1 _ -z y inchessem••*-•c.-••.`wft-• <br /> N..a•n d Ml U.-i us"�-6 <br /> 2. Depth of percolation tests : ;: M 1 inches Co-" � .....,-Pne <br /> 3. Percolation rate 39. 3 mpi , <br /> 4. Land slope % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> 71.1-0 <br /> i.,GQ gpd x 0.83 sq. ft./gpd = oo sq. ft. t kodl-" 6 <br /> 2. Select width of rock layer (10 feet or less) = jd ft. <br /> 3. Length of rock layer = area y width = Rock Bed <br /> Sid sq. ft. + Vic,,_ft. = _� ft. ....�., ,.•..•.....�.•. �...,.�.�.,.•. <br /> f.•.f•••:.f.• •.• idth 510 f <br /> E. ROCK VOLUME �- Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; 5� <br /> S-�i sq. ft. x _J; ft. =1, _cu. ft. o <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 5c) cu. ft. y 27 = Z-cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> ,.2�cu. yd. x 1.4 ton/cu. yd. =3o tons. <br /> F. ADSORPTION WIDTH Absorption Width Stang Table <br /> Percolation Rau+ Gelleas I Raue of <br /> 1. Percolation rate in top 12 inches of soil is,L i mpi ,nH;n�,e,,e.lSoilTeuurs perdayW Abamgtion-ft <br /> ��' �� SL,ch(MPI) sq rre fax to R t Layer <br /> ua c a Y 14 �, Pte-. 46 -100dN <br /> 2. Select allowable soil loading rate from table; l Fa,tarthan 0.1• Coarse S" --. --- <br /> 0.1 to SSand 1.20 1.00 <br /> gpd/ftp 0.1 to 5 . Fine Sand•• 0.60 3.00 <br /> 6 to 1s SM47 Loam 0.79 1.33 <br /> 16 to 30 t•oare 0.60 2.00 <br /> 31 toss 1 Loam _LM_ x.2.40- <br /> 3. Calculate adsorption width ratio by dividing rock layer , <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; S1.,»era„n Cay - -- <br /> 1.20 gpd/ftziis gpd/ftz = 2. oil S►; <br /> • Sal too coarse for tnsallauon of a <br /> standard system. <br /> See 7080.0170 Subp 2.0.3,page 26. <br /> 4. Multiply adsorption width ratio by rock layer width to get •• Soil having 50%or moa ofGnesand <br /> plus very fine sand. <br /> required adsorption width; soil too heavy far insUlla.iott of a <br /> •••standard system. <br /> �,7 x _�f t = f t See 7080.0210 Subp s.A,Pie 33. <br />