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OSTP Mound Design <br /> UNIVERSITY <br /> Worksheet >1% Slope OF MINNESOTA , <br /> Control Agency <br /> 1. SYSTEM SIZING: Project ID: v03.19.15 <br /> A. Design Flow: GPD TABLE Ma <br /> B. Soil Loading Rate: 0.45 GPD/ft2 AM�M ATM 7M <br /> ,hn ns <br /> C. Depth to Limiting Condition: 1.5 ft <br /> Noir." a..vw�. <br /> r"�eoaMe"ae. LMS Ab <br /> ow &mks" r <br /> AINT <br /> D. Percent Land Slope: 4.0 % 01 ao. N"'w"" aw $bNo"" <br /> WdW) aw (role) aro <br /> E. Design Media Loading Rate: 1.2 GPD/ft2 .01 - 1 1 <br /> F. Mound Absorption Ratio: 01105 1.2 1 1.8 1 <br /> 1 b MNtl 0.8 2 1 1.8 <br /> TAM I "n0 Orr <br /> Ip s b" 0.78 1A 1 1.8 <br /> WOW 1a b 30 0.0 2 0.78 2 <br /> �W Tewm-do {A 311045 0A 2A 0.72 2 <br /> P11C MC As b so OAs 2.8 0.8 2.8 <br /> s 6Q1pf 1.0. 1.3.Lo.0.2.4.2.6 s 12 1 b 120 s 0.3 s 3 <br /> �12D <br /> 61-120nlpi OR 5.0 s12 Systems with these values are not Type I systems. <br /> i 120 nt*r >s.0• ss• Contour Loading Rate(linear loading rate)is a <br /> recommended value. <br /> 2. DISPERSAL MEDIA SIZING <br /> A. Calculate Dispersal Bed Area: Design Flow+Design Media Loading Rate-ft2 <br /> GPD + 1.2 GPD/ft2 = ft2 <br /> If a larger dispersal media area is desired, enter size: ft2 <br /> B. Enter Dispersal Bed Width: 10.0 ft Can not exceed 10 feet <br /> C. Calculate Contour Loading Rate: Bed Width X Design Media Loading Rate <br /> 10 ft2 X 1.2 GPD/ft2 = 12.0 gal/ft Can not exceed Table 1 <br /> D. Calculate Minimum Dispersal Bed Length: Dispersal Bed Area +Bed Width - Bed Length <br /> �ft2 <br /> + 10.0 ft = 50.0 ft <br /> 3. ABSORPTION AREA SIZING <br /> A. Calculate Absorption Width: Bed Width X Mound Absorption Ratio =Absorption Width <br /> 10.0 ft X 2.6 = 26.0 ft <br /> B. For slopes>1%, the Absorption Width is measured downhill from the upslope edge of the Bed. <br /> Calculate Downslope Absorption Width:Absorption Width - Bed Width <br /> 26.0 ft - 10.0 ft = 16.0 ft <br /> 4. <br /> DISTRIBUTION MEDIA: ROCK <br /> A. Media Volume:Medla Depth below and above pipe X Length X Width <br /> 0.75 ft X 50.0 ft X 10.0 ft= 375 ft3 + 27 = 14 yd3 <br />