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2007-P11181 - new septic
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2007-P11181 - new septic
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Last modified
8/22/2023 4:27:26 PM
Creation date
6/27/2019 2:29:25 PM
Metadata
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Template:
x Address Old
House Number
1140
Street Name
Town Line
Street Type
Road
Address
1140 Town Line Road
Document Type
Septic
PIN
3011823320006
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> Eninsated Sews;e Flows in Gallons per day <br /> A. FLOW d <br /> Estimated �.O gpd i n ber Type l TM a Type M N <br /> or measured - x 1.5 = - gpd. <br /> 2 300 2Z 180 W% <br /> the <br /> B. SEPTIC TANK LIQUID VOLUMES 4 � 3x75 2� � <br /> 5 750 450 294 W <br /> Dl-/000 gallons 6 900 525 332 Type L <br /> 7 1050 600 370 11 or <br /> 8 1200 675 408 M <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer= "-lo xt='inches feet > <br /> IVanaer or M -1Jquia ospsdry«an .gym <br /> 2. Depth of percolation tests= i �" inches aerie I dUp" <br /> 00 <br /> 3. Texture �n>� Percolation rate C• 'i mpi =3.w`� 103000 i`sm `zoS O <br /> s tK 6 Ism mo 3000 <br /> 4. Land slope 3 % '•"'"" 2000 5000 4= <br /> D. ROCK LAYER.DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> LA 5 L) gpd x 0.83 sq. ft./gpd = -z,f)--� sq. ft. +,o-,o y)o <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = /o ft. <br /> 3. Length of rock layer= area+width <br /> 4)o sq. ft. + L4 1_ ,... �.�.:. <br /> Width /o ft <br /> <120mpi <10' Length- Ljj-ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; i o sq. ft. x 1 Os- <br /> ft. = L430 cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 4 3o cu. ft. +27 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; J i, cu. yd. x 1.4 <br /> ton/cu. yd. = -�Q tons. <br /> F. ABSORPTION WIDTH Absorpdon wwtb sizing Table <br /> 1. Percolation rate in top 12 inches of soil is mpi Poe adoowtaa Gallam w000(Abamptiott <br /> Minutes pa lath Soil Texture per day pa width to Rock, <br /> Texture t;�A A Lota-m (MPl) =f= layerWIMM <br /> Faster than 0.1 Coarse Seed 120 1.00 <br /> 0.1 to 5Sand 120 1.00 <br /> F <br /> 2. Select allowable soil loading rate from table; 0.1 os Seed 0.60 2.00 <br /> WS 5.to 15 sandyloan 0.79 1.52 <br /> 4� gpd/ft2 16to30 LAM 0.60 2.00 <br /> 31 to 45 Sib Loam 030 2.40 <br /> 46 to 60 Clay LOM 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer slower than 120 020 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2+ "1s/ gpd/f2= <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a,c, x !o ft= ft <br />
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