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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewne flows in Gallons pw day <br /> Estimated y5 o gpd ► 17*1 Type TM to <br /> or measured - x 1.5 = - gpd. <br /> 2 300 2Z 180 <br /> 300 218 <br /> B. SEPTIC TANK LIQUID VOLUMES 4 60 375 256 <br /> 5 750 450 294 <br /> gallons 6 900 525 332 Tn 1. <br /> g 7 1050 600 370 <br /> nor <br /> 8 1200 675 408 m <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer=me ao a' inches feet i -P-,y <br /> nwaa«Or Nhsu am uww�ao.m1 wM Mm m,ro,us <br /> 2. Depth of percolation tests= t ;L. inches �� "n1adet <br /> 125 1500 <br /> 3. Texture Lan:3 Percolation rate L4. 2, mpi = Ism 2000 <br /> s rh ow ' <br /> 4. Land slope y % 7.Aar v "W >� <br /> D. ROCK LAYER.DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> 4.0 gpd x 0.83 sq. ft./gpd =-2.3..sq. ft: )o'5D=�►)o"' <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = / o ft. <br /> 3. Length of rock layer= area+width= --•� y� y -xr <br /> = �, .�..�dry.�.., wi <br /> H1 oSq. ft. /� ft. ft. �.r��. . �.Q <br /> Width -IDft <br /> <120mpi <10' Length--4j-ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; 4)o sq. ft. x i. <br /> ft. = H:30 cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu.yd. to get cubic yards; <br /> zo cu. ft. +27= I., cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; Z(, cu. yd. x 1.4 <br /> ton/cu. yd. _ tons. <br /> F. ABSORPTION WIDTH ANoMtkm WWtb SlzWg Uble <br /> 1. Percolation rate in top 12 inches of soil is H.a mpi Pa.ola000Ramia callom wocofAes�poaa <br /> Mi oow loch Soil Texture per day per width to <br /> Texture L.-?�'Z �-b b wl (NIper agtmte foa Dyer width <br /> Faster than 0.1 Comae Said 1.20 1.00 <br /> 0.1 to 3 Said1.20 I.00 <br /> 2. Select allowable soil loadin rate from table; 0.1 to 5 Fine seta 0.60 2.00 <br /> g 6 to 15 Satdly LAM 0.79 1.52 <br /> .Ll J! gpd/ft2 16 to 30 Loam 0.60 2.00 <br /> 31 ro 45 Silt Loam 030 2.40 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> '0.'owes thm 1 020 6*.00 <br /> 20 Clay 0.24 500 <br /> 3. Calculate adsorption width ratio by dividing rock layer s1 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ftz+ -Luc gpd/ft2= <br /> 4. • Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a•�� x1�ft = ft <br />