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1998-010276 - new septic system
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1998-010276 - new septic system
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Last modified
8/22/2023 4:27:24 PM
Creation date
6/26/2019 1:52:04 PM
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x Address Old
House Number
1020
Street Name
Town Line
Street Type
Road
Address
1020 Town Line Road
Document Type
Permits/Inspections
PIN
3011823320005
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MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons per day <br /> (Apd) <br /> Estimated -S gpd Number Type I Type 11Type Mof <br /> Type <br /> or measured x 1.5 = gpd. Bedrooms IV <br /> 2 300 225 180 <br /> B. SE TIC TANK LIQUID VOLUMES a 460500 3755 2256 60% <br /> of the <br /> values <br /> 0 0 0 gallons 6 790500 52505 332 �1. <br /> 7 1050 600 370 u or <br /> 8 1200 675 408 W <br /> C. SOILS(refer to site evaluation) I I I I columns <br /> 1. Depth to restricting layer= 20 inchesfeet Srptie Taak .citieslin aauns <br /> Iiyuidcapacily <br /> 2. Depth of ercolation tests =%Z inches N°nrr Mini Capacity <br /> yuid liquid gedisposal <br /> capacity s it w m disposal& <br /> Bedn,ums capacity garbage disposal lift inside <br /> 3. Texture t 2,,rlas 750 1125 1500 <br /> �.- Percolation rate /� mpi 3:r4 1000 1500 2000 <br /> s.,r n 1500 2250 woo <br /> 4. Land slope % 7.s,r9 20M 30M 4000 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required a--a of rock layer: A x 0.83 = <br /> gpd x 0.83 sq. ft./gpd =._M sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /p ft. <br /> 3. Length of rock layer = area-width <br /> ae°. <br /> poa°oo.00c' <br /> 3 71 sq. ft. = ft. _ 0Z ft. opaoS � <br /> a0 d 8 a:6 6 60000 ��� <br /> 4a..4 `o�Qo <br /> Width /D ft QooA . oopao a o> <br /> <120mpi <10' Length -3 ftP <br /> E. ROCK VOLUME <br /> >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock,�70 sq. ft. x / <br /> ft. =vle cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> .3 7d cu. ft. -27=Z.7, Z cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;1-7, 7cu. yd. x 1.4 <br /> ton/cu. yd. _ tons. <br /> F. ABSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is /-I-mpi Percolation Rate in canons RatioorAbso"oo <br /> Texture�r Z,e,,4 .ten Min(MpInch Soil Texture �=f. wayeridthrRock <br /> width <br /> Faster than 0.1 Coarse Sand 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; o., 5 sand ��,.6zo���, l.00 <br /> A41.15 andy loam' /C 0,79/ 1.52 <br /> gp ft2 16 t.35 <br /> o am 0.60 <br /> �r d/1 t- 31 to 45 Silt Loam 0.50 2.40 <br /> 46 to 60 Clay Loam 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer Slower than 120 clay 0.20 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2= f 7 q gpd/ft2= /.S-Z <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> X A'Sft <br />
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