My WebLink
|
Help
|
About
|
Sign Out
Home
Browse
Search
1997-009688 - new septic system
Orono
>
Property Files
>
Street Address
>
T
>
Thoroughbred Lane
>
2605 Thoroughbred Lane - 04-117-23-11-0022
>
Septic
>
1997-009688 - new septic system
Metadata
Thumbnails
Annotations
Entry Properties
Last modified
8/22/2023 5:06:39 PM
Creation date
4/24/2019 9:27:42 AM
Metadata
Fields
Template:
x Address Old
House Number
2605
Street Name
Thoroughbred
Street Type
Lane
Address
2605 Thoroughbred La
Document Type
Septic
PIN
0411723110022
Supplemental fields
ProcessedPID
Updated
There are no annotations on this page.
Document management portal powered by Laserfiche WebLink 9 © 1998-2015
Laserfiche.
All rights reserved.
/
31
PDF
Print
Pages to print
Enter page numbers and/or page ranges separated by commas. For example, 1,3,5-12.
After downloading, print the document using a PDF reader (e.g. Adobe Reader).
View images
View plain text
.c l• <br /> Z33. DOWNSLOPE WIDTH <br /> 1. <br /> 1. If landslope hs-0% �more,subtract rock layer width from <br /> adsorption width to obtain minimum downslope dike toe <br /> a te.� ft- 10 ft= ' _feet <br /> 2. Calculate Minimum-mound size based on geometery: <br /> a. Determine depth of clean sand fill at upslope edge of rock <br /> layer: Separation� .feet <br /> b. Multiply rock layer width by landslope i>tet~t Celrel• <br /> to determine drop in elevation; tees R• .a <br /> Slope Difference s.D'ralea t..'c <br /> b. <br /> /o x)_%+100=3_feet S1•p:Oifi.ni,�t_ t <br /> UpS10De WIAt11 <br /> c. Add depth of clean sand for separation (2a) 12,feet Roek Bad Width <br /> at upslope edge,depth o£rock layer,(1 foot) to depth.of in feet oown•lope Width <br /> cover(1 foot)to find the mound height at the upslope edge - 1te` <br /> of rock layer, <br /> ). *;L- ft+ ift+ ift= Z.', feet <br /> d. Enter'table with landslope and upslope dike ratio. <br /> Select dike multiplier of 3 <br /> e. Multiply dike multiplier by upslope mound height <br /> to find upslope dike width: -z../? x _I_feet <br /> f. Add depth of clean sand for slope difference (2b)at <br /> downslope edge,to the mound height at the upslope edge <br /> of rock"layer(2c) to,find the downslope height; <br /> 3.Z ft+ .-.a, ft= 3,y feet <br /> g. Enter table with landslope and downslope dike ratio. <br /> ;Select dike multiplier of 4.2,5- <br /> h. <br /> .3Sh. Multiply dike multiplier by downslope mound height <br /> to get downslope dike width: 0.3S x -3.u =I-'�- feet <br /> i. Compare the values of step G.1 and Step G.2h Select the <br /> greater of the two values as the downslope dike width; _ <br /> feet >: <br /> U•alOpa Wlotn',}'• :;a,:::. ;:'r 034 :: is#::::::`::;: <br /> j. Total mound width is the sum of -LL..feet <br /> upslope dike(G.2e)width plus rock <br /> .:.r....wr:.:w. <br /> layer width(D:2)plus a u•s •a W1etn a Wl•th <br /> 3: teat • <br /> downslope dike width(G.2i) 3 <br /> la, ft+_ o ft+ 17 ft= _feet <br /> .:.Y Vie•' :100-11.1.0•WI•tn ir`•• <br /> k. Total mound lengtf=is the sum of <br /> upslope dike width(G.2e)plus rock layer <br /> len D.3)plus*upslopie dike width (G.2e); r ' .° ::$>t:;:.•;.. •<':. : '::: <br /> ft+ 7S ft+)x ft= _feet <br /> V? <br /> Total Length <br /> Vownslope UPSIOPe <br /> 31 4:1 5:1 0 7:1 3:1 4:1 5:1 0 71 83 <br /> s.lope <br /> 0... <br /> 3.0 40_. _SA,_..„ i0 7.0. 3.0 40 5.0 610 7.0 8A <br /> 1 3A9 4.17 !36 6.31 7S3 2.91 3.85 4.76 SA6 654 7A1 <br /> 2 319 435 S56 M 8.14 2M 3.70 454 S36 6,14 690 <br /> 3 330 454 JIM 732 8.16 2.75 357 435 SAO 5.79 6:15 <br /> 4 3A1 476 6.25 7.09 9.72 2.68 3.45 4.17 4.114 SM 6.06 <br /> 5 3S3 SAO 467 157 10.77 2.61 333 400 4A2 5.19 S21 <br /> 6 3A6 5.26 7.14 938 12M 2.54 3.231 3.M 441 493 SA1 <br /> 7 3,110 556 Me 10.34 13.73 148 3.12 3.70 423 470 513 <br /> 8 335 SAO 833 1134 1591 142 3.03 337 4A5 449 4 S <br /> 9 411 6.25 9A9 13.04 18.92 236 1% 345 390 430 466 <br /> 10439 667 1010 15.00' 2333 231 2.86 337 335 412 4A4 <br /> it 4A• 7.14 11.11 17AS 30A3 236 17O 333 3A1 3.95 436 <br /> 12 4A9 7.0 1250 21A3 4395 121 170 3.12 149 3A0 4115 <br />
The URL can be used to link to this page
Your browser does not support the video tag.