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1996-007709 - new septic system
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2570 Thoroughbred Lane - 04-117-23-11-0016
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1996-007709 - new septic system
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Last modified
8/22/2023 5:06:11 PM
Creation date
4/23/2019 11:26:05 AM
Metadata
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Template:
x Address Old
House Number
2570
Street Name
Thoroughbred
Street Type
Lane
Address
2570 Thoroughbred La
Document Type
Septic
PIN
0411723110016
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flow in Gallons per Day(gpd) <br /> Estimated r)SO gpd Nwn� <br /> or measured x 1.5 = gpd. Bedrooms lYPe I II type 1II Type IV <br /> 2 300 225 180 60% <br /> of <br /> B. SEPTIC TANK LIQUID VOLUMES 4 6 0 3755 256the <br /> -lo-LO 16 )-/Q oy gallons 6 900 525 35 750 450 32 0the <br /> 7 1050 600 370 <br /> 8 1200 675 408 <br /> C. SOILS (refer to site evaluation) � IWC ,,®® <br /> 11 I! SgecT-t C�.ue <br /> 1. Depth to restricting layer= 1 - :aof Ll inches Bed = > <br /> 2. Depth of percolation tests = t a inches `PH-0 `""m'' <br /> 3. Percolation rate /0-1 mpi 2i«tea` 17.000 1'.'125 <br /> 500 <br /> 5 a 6 1.500 <br /> 4. Land slope �'3 % 7 o<8 2.000 0o <br /> ova 9 See fig.C-6 (x 1.5) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = , <br /> n o gpd x 0.83 sq.ft./gpd = (,az sq. ft:})0'5o=(o'dy° <br /> 2. Select width of rock layer(10 feet or less) = /0 ft. <br /> 3. Length of rock layer= area_width = Rock Bed <br /> !.j -L-sq. ft. 0 ft. _q ft. <br /> 1tiSJJ••titi•JJ.•titi•J..titiN•J•1ti•JJ••�ti•J••ti1•.JJ••tti•JJ••titi•JJ••{1.JJ••tti•J••ti�•JJ••titi•JJ••titi•JJ••titi•JJ••tititi••JJ.••ti��•• <br /> <10 ft.idth <br /> .t.ti •N• •t• •ti•t •ti.S•ti. <br /> •J•J•J•J•J•J•J•J•J•J•J•J•J•hJ•J• <br /> E. ROCK VOLUME Length <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> (,. sq. ft. x/_o-<- ft. =r.L`�cu. ft. <br /> 2. Divide cu.ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 4�cu.ft. i 27=�cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> cu. yd. x 1.4 ton/cu. yd. =_Z_t� tons. <br /> F. ADSORPTION WIDTH c.LA q L o A v✓1 Absorption width Si-6n Table <br /> 1. Percolation rate in top 12 inches of soil is >o mpi Percolation Rabe tea» Raw al <br /> Minatmperinch Soil Texture P'"y -dhW <br /> FrQ. •spa <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse Sand 1.20 1.00 <br /> / 2 0.1 to 5 Sand 1.20 1.00 <br /> L4 gpd/ft- 0.1to5 Fine Sand- 0.60 2-00 <br /> 6 to 15 Sandy Loam 0.79 1-52 <br /> 3. Calculate adsorption width ratio by dividingrock laver 16 co 30 Loam 0.60 2.00 <br /> 31 to 45 Silt Loam OSO 2.40 <br /> loading rate of 1.20 gpd/A2 by allowable soil loading rate; 46 to 60 Clay Loam 0.45 2.67 <br /> 1.20 d f-2 i 61 t0120 Clay 024 5_00 <br /> gp / ,y gpd/ft2= (off Slower than 120 Clav <br /> '•Soil having 5096 or more of fine or very fine sand <br /> 4. Multiply adsorption width ratio by rock laver width to get <br /> required adsorption width; <br /> a.G0 x/oft= ab.1 ft <br />
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