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MOUND DESIGN WORKSHEET Is , ij <br /> 0 f <br /> (For Flows up to 1200 gpd) � ' <br /> A. FLOW Eshmatcd Scwagc Flows in Gallons per day <br /> Estimated 4 50 gpd �3309"O--� (gpd' <br /> . umoer <br /> of { Type I 'type 11 type� Type <br /> or measured x 1.5 = gpd. Bim,I I„ <br /> B. SEPTIC TANK LIQUID VOLUMES u 180 <br /> 700 218 <br /> 600 773 236 <br /> Z 00 o gallons 3 730 430 2% 0 <br /> 6 900 523 772 1r.t. <br /> 7 1030 600 370 lot <br /> 8 1200 673 408 �..,.. <br /> C. SOILS (refer to site evaluation) <br /> 1. Depth to restricting layer= 1 inches 5"m T"`Qpw,"m <br /> 2 Depth of percolation tests = ""'°°"°` "'"""""''L"''"°.Y..h <br /> l� inches tt.a�.,. Co" e...., .., <br /> 3. Percolation rate -Z mpi °y <br /> t_-v <br /> 4. Land slope 10 .0 % �•.+ <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = �� � IG � _ � Io�rtZ <br /> X15 c) gpd x 0.83 sq. ft./gpd = 5J sq. ft. ` <br /> 2. Select width of rock layer (10 feet or less) = 10 ft. <br /> 3. Length of rock layer = area+width = Rock Bed <br /> Wto sq. ft. + I o ft. I ft. ,.,.,.�.,..........,.;.,.,.,.,.,.,.•. <br /> ,:�:.r.f••�r•f•f•� f•f•f•r•r•f•f• <br /> idth :510 ft <br /> ,.•..,.•.•,•,•,.,•,.ti.,lulu.,., <br /> 1.1•f•I•t•1•f•I•t t•I•t•t•t••••I• <br /> ,I•I•I•�•t•�•!•I•I I•I.1•r•I•I•I• <br /> ,. •,•,lulu.,•,lulu•,•,.,.,•,.,•♦ <br /> E. ROCK VOLUME �- Length -( <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> I O sq. ft. x L_ft. _q10..cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 4 t cu. ft. + 27-16 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> I(o cu. yd. x 1.4 ton/cu. yd. _ tons.* l a?o <br /> F. ADSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in to 12 inches of soil is�•d m i in Miction R tally p Roof_' <br /> 1 r� p in Minute per Soil Tei�,re per day per Absorption.�atn <br /> V j/ 110-3t Mr P f C4'�dQ-N�' � c�AC7 <br /> Inch(MP!) agturc foot to RW Width <br /> Layer <br /> 2. Select allowable soil loading rate from table; faster than o.1• coarse Saw -. --- <br /> o.ttos Sand1.60 1.00 <br /> r gpd/ftiz o.1 to s•• Fine Sand•• 0.60 zoo <br /> s°0�r <br /> 311045 Sill Loam 0.50 2.40 <br /> 3. Calculate adsorption width ratio by dividing rock layer 46 to 60 clay Loam o.43 2.67 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; Slo crtha�n Clay o.24 s_oo <br /> 1.20 gpd/ftz+�(s.,0 gpd/ft'= 2 r cid 120••• <br /> • Soil too coarse for insw1mion of a <br /> standard system. <br /> See 7080.0170 Subp 2.0.3.ppage 26. <br /> 4. Multiply adsorption width ratio by rock layer width to get •• Soil having 30%or more of fine sand <br /> plus very fine sand. I <br /> required adsorption width; Soil too heavy for insudladon of a <br /> •••standard system. <br /> �.Old x 10 ft = ft See 7oao.o2lo subp s.A.page]]. <br />