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1996-008472 - new septic
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1520 Tanglewood Road - 26-118-23-32-0010
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1996-008472 - new septic
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Last modified
8/22/2023 4:17:08 PM
Creation date
4/17/2019 10:12:29 AM
Metadata
Fields
Template:
x Address Old
House Number
1520
Street Name
Tanglewood
Street Type
Road
Address
1520 Tanglewood Road
Document Type
Septic
PIN
2611823320010
Supplemental fields
ProcessedPID
Updated
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PRESSURE DISTRIBUTION SYSTEM ENO PERFORATION OF A PERFORATED LATERAL_ <br /> firer Co. <br /> I. Select number of perforated laterals —3 Too"M <br /> Lay <br /> s►at Geeteenle Fearre(or rev <br /> •,..Leo"SOW Leger =ienr of her War"oo.ered <br /> 2. Select perforation spacing a .3 feet. <br /> r P Iferetlee 00111e41 Meruelttelly <br /> late Gap fiver Too <br /> 3. Since perforations should not be placed closer than 1 ft. to P"l " Rea aveLocto 121 r�°'. <br /> rale Fl.Id n« ._ of Race Laver <br /> the edge of the rock layer(see diagram), subtract 2 ft from Perfe►erlene'Looared of <br /> Gteae Saw LayerBertere of Leieral <br /> the rock layer length. <br /> Or1allo1 Sell PreoeAy Scerlrlee <br /> / -2 ft. feet. Before Plods° Seoul Layer <br /> Rode layer length TABLE OF PERFORATION DISCHARGES IN CPM <br /> 4. Determine the number of spaces between perforations. Head Per-'Oration liar e:er(inches) <br /> Divide the length above by perforation spacing and round '/a r�r <br /> down to nearest whole number. <br /> • 1.Oa S6 0.7 <br /> 1.5 0.69 0.90 <br /> Length perf. spacing —35 ft.+ 3 ft 13 spaces 2.ob OM IAA <br /> 2-5 039(3) (2) 0 0.98 128 <br /> 5. Number of perforations is equal to one plus the number of s.o 1.13 147 <br /> perforation spaces . <br /> 63 <br /> aL:se 1.0 foot of head for residential systems. <br /> ,L / bUse 2.0 feet of head for other establisharents <br /> 13 spaces + 1 =�perforations lateral <br /> M•o��JMM•r��1 r�efe10� <br /> PW%..W <br /> 6. Multiply perforations per lateral b number of laterals to ch 1- in <br /> PYP P Y �•, � I � ��h 1s�1cn 2.0 i,c:, <br /> get total number of perforations. 2.5 14 s 28 <br /> 1326 <br /> 12 166 25 <br /> uta, x ,/,��_ perforations. 4.0 11 15 23 <br /> 5.0 10 14 22 <br /> 7. Determine required flow rate by multiplying <br /> number of perforations by flow per perforation <br /> a d.7 oi <br /> _ gPm• <br /> rwro 1.0"10 •r oo a ret7ssR mn11a1rnoe rrsrlr <br /> P� gpm/peef <br /> 8. If laterals are connected to header pipe as shown on upper <br /> example, to select minimum required lateral diameter; enter <br /> table with perforation spacing and number of perforations <br /> per lateral. Select minimum diameter for <br /> perforated lateral = inches. <br /> urevr 0/q./ryr•IrJ♦r.f ur[I41 1s <br /> `n(J ML•Il P.r.rlrq.A.Ar.e <br /> 9. If perforated lateral system is attached to manifold pipe near --,-- <br /> the center,lower diagram,perforated lateral length and <br /> number of perforations per lateral will be approximately one <br /> half of that in step 8. Using these values,select minimum <br /> diameter for perforated lateral = �/z inches. <br />
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