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2003-P06637 - new septic system
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1085 Tamarack Drive - 26-118-23-31-0017
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2003-P06637 - new septic system
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Last modified
8/22/2023 4:16:41 PM
Creation date
4/16/2019 12:01:46 PM
Metadata
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Template:
x Address Old
House Number
1085
Street Name
Tamarack
Street Type
Drive
Address
1085 Tamarack Drive
Document Type
Septic
PIN
2611823310017
Supplemental fields
ProcessedPID
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.*FROM RYS PHONE NO. : 4422091 Jul. 02 2003 09:17AM P5 <br /> MOUND DESIGN WORKSHEET 5 <br /> (For Flows up to 1200 gpd) <br /> A. FLOW Estimated Sewage Flows in Gallons par day <br /> Estimated �-� gpd Nwnbu Type l Type n <br /> ofryye m Type <br /> or measured x 1.5 = gpd. <br /> z Sao ns leo <br /> B. SEPTIC TANK LIQUID VOLUMES 4 6W � 256 ofdx <br /> Ty <br /> 17Z 5,C7 gallons 6 's o s�25 33s In <br /> 7 1050 600 370 n Q <br /> 8 1200 675 408 Ip <br /> C. SOILS(refer to site evaluation) , <br /> 1. Depth to restricting layer= a inches feet m m"of MW mtkl>we naml rmy w. g <br /> 2. Depth of percolation tests= /Z inches .ate a,< « <br /> 3. Texture Percolation rate ? o ; i4 oxit .1"o� <br /> 4. Land slope % 7.A MY 15M WO ao300°00 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer:A x 0.83 = <br /> _�_gpd x 0.83 sq. ft./gpd=6-2 Esq,ft: <br /> 2. Select width of rock layer(max 10' if X120 rnpi max 5') =/b ft. <br /> 3. Length of rock layer=area--width <br /> 23sq' ft.¢ Jd ft. = 62 ft. <br /> Width eft - '' <br /> c120mpi c10' e L,engtbg�2Z ft <br /> E. ROCK VOLUME >120mpi [5 <br /> 1. Multiply rock area by rock depth to et cubic feet of rock;l� scl.ft. x <br /> ft__ cu.ft. <br /> 2. Divide cu_ ft.by 27 cu. ft/cu.yd. to get cubic yards; <br /> Z.72cu. ft. +27=�7,9 cu.yd. <br /> 3. Multiply cubic yards by 1.4 to get we' ht of rock in tons; -zjcu.yd. x 1.4 <br /> ton/cu. yd. _, tons. <br /> F. ABSORPTION WIDTH Absorption width siting Table <br /> I. Percolation rate in top 12 inches of soil is /(� pi Petoal.00eAMin 0212M xaseernbaaotyt;<,p <br /> Texture <br /> Kowa w Imb Soil Uum pu day� Wi to to RD& <br /> root L.r«Wwm <br /> Faster than 0.1 Co Sana 120 1.00 <br /> 0.1w5 Sam 120 1,00 <br /> 2 Select allowable soil loading rate from table; 0.11465 5 Fmo SMd 0.60 2.00 <br /> 61015 S.aay Loam 0.79 1.52 <br /> x6.49 gpd/ft2 16x030 Loam 0.60 zoo <br /> 31 to 45 Silt La® 030 2.,40 <br /> 46 to 60 Gey L a® ods 2.67 <br /> 6010120 Gay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer Slow°dl- c1v 020 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loadmi rate; <br /> 1.20 gpd/fF= r D gpd/ftz= c <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> � x�ft= waft <br />
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