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MOUND DESIGN WORKSIIE:[-I' I �p��u /�o.�►^ J <br /> (N)r Flaws up to 1200 gpd) <br /> A. FLOW <br /> F:stunrod Sc.mgc floes m('i.lkm.M U.1(� <br /> Estimated 600 gpd N,�„� <br /> or measured x 1.5 = d. °1 �1 �`11 Type i11 TYr,IV <br /> -- 8P ne&aorrtx <br /> z loo 225 leo 40,E <br /> B. SEPTIC TANK LIQUID VOLUMES 4 60 3°5 256 <br /> Oo gallons 6 9900 s s iii U. <br /> 1o� ,�jal6v, puV-P IT..1 k 8 1� 6 ;� <br /> C. SOILS (refd to site evaluation) <br /> Number s�.�.•r <br /> � ow�w <br /> 1of �. Depth to restricting layer = 0'21 inches BC,&00= <br /> 2. Depth of percolation tests = 12 inches <br /> 3. Percolation rate 14 - / 7.1 mpi 2 or km 750 1.125 <br /> 3 a 41.000 1.500 <br /> 4. Land slope 3 %v 5 or 6 11.5w 1250 <br /> 7 or 9 2.000 3.000 <br /> over 9 Sae fig.C-6 (x 1.5) <br /> D. ROCK LAYER DIMENSIONS <br /> L Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> SOU gpd x 0.83 sq. ft./gpd = SOO sq. ft. <br /> 2. Select width of rock layer(10 feet or less) _ /o ft. <br /> 3. Length of rock layer=area_width = Rock Bed <br /> t60 sq. ft. to ft. = So ft. �.�.�•�•�•1..•�•Y�•�•�•N�•t.« <br /> J•J•J•J•J•J•MJ•J J•J•J•J•J•J•J• <br /> 1.�•ti.�•ti•t.ti•ti•Yt•M1•�•L•�.�.5 <br /> J•J•J•I•J•J•J•J•J J•J•J•M•J•J• ldth :510 ft. <br /> 1.1.1.1.1.1.1.1.1 J•J•J•J•J•J•h <br /> ti•tiK•1i•1•�•ti•�•ti•�•S•Sr•tiK•tiKK <br /> •J•1•J•1•f•1•MJ•1•Hh1.1•HNh <br /> E. ROCK VOLUME Length --+ <br /> L Multiply rock area by rock depth to get cubic feet of rock; <br /> SOU sq. ft.x I ft. = Soo cu.ft. <br /> 2. Divide cu.ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> Soo cu.ft. =27= IS.S cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> j,,S cu.yd.x 1.4 ton/cu.yd. = 96 tons. <br /> F. ADSORPTION WIDTH Width&zhng le <br /> 1. Percolation rate in top 12 inches of soil is 16-A mpi p��,�kRadof <br /> OZ.��, Soil Texture n ,i&k ft <br /> 2. Select allowable soil loadingrate from table; �. � <br /> 0 6 Faster than 0.1 Sand 120 1.00 <br /> gpd/ft2 0.1 toy Sand 120 1.00 <br /> 0.1 to 5 Fine Sand- 0.60 2.00 <br /> 6 to IS &andy Loam 0.79 1.52 <br /> 3. Calculate adsorption width ratio by dividin rock la 16 to Loam 0.50 2.00 <br /> g �'er 31 to 4 45 5 Silt Loam OSO 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 Cla Loam 0.45 2.67 <br /> 1.20 gpd/ft2 0.6 gpd/ftp = 0_0 61 t0120 Clay 024 _00 <br /> Slower than 120 Clay <br /> s.nd. <br /> 4. Multiply adsorption width ratio by rock layer width to get "Sail hiving 501E a mac of fine or vay finr <br /> required adsorption width; <br /> a•o x to, ft = _,'o ft <br />