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MOUND DESIGN WORKSHEFF <br /> (For flows up to 1200 gpd) <br /> A. FLOW tisumated Sewage Flow an Gallonsper Day(&pd) <br /> Estimated 60o gpd Numbes <br /> or measured x 1.5 = gpd. Ilea°0o� Type' Type° lope"' �a IV <br /> 2 300 223 Igo sos <br /> 13. SEPTIC TANK LIQUID VOL-UMES i boo 375 256 ,d. <br /> � P, laob gallons 6 9 o su 332 <br /> l low �'"� tam k s ix�oo 6°s +a <br /> ��. <br /> C. SOILS(refer to site evaluation) N � - <br /> 1. Depth to restricting layer= 2 inches of <br /> 6e&ooma <br /> 2. Depth of percolation tests = 12 inches <br /> 3. Percolation rate 171.20 mpi 2 1.125 <br /> 3 or c '� <br /> 4. Land slope 12% 0, 7 % 7 or a 1.500 <br /> s '2.000 2, 0 00000 <br /> over 9 See fig.c-6 (x Is) <br /> D. ROCK LAYER DDAENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = <br /> 660 gpd x 0.83 sq. ft./gpd= Sao _sq. ft. <br /> 2 Select width of rock layer(10 feet or less) = 16 ft. <br /> 3. Length of rock layer =area i width= Rock Bed <br /> Soo sq. ft. y to ft. = A6 ft. <br /> t•f•1•l•l•J•Hf•1 t•l•I'•r•f•f•f• <br /> t•1•ti•ti•1•S•�•ti•Y1•�•ti•�•ti•ti•S•� <br /> r•r•r.r•1•r•f•r•�r•�•r•r.r•f•r• kith <_10 ft <br /> t•ti•ti•ti•L•S•ti•ti•Yti•�•�K•ti•ti•ti•ti <br /> J•1.1M•t•h1•f•f•t•f•IY•1•l•�• <br /> S•tiK•ti•ti•1••{.•ti•Mvti•�•ti•MtiM•ti <br /> •t•t•t•l•r•�•1•J•f•hNr•1•f•r•1• <br /> E. ROCK VOLUME <br /> L Multiply rock area by rock depth to get cubic feet of rock; <br /> Soo sq. ft. x 1 ft. =See cu. ft. <br /> 2. Divide cu.ft.by 27 cu. ft./cu.yd. to get cubic yards; <br /> Soo ft. 27= I .S cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weit of rock in tons; <br /> cu.yd.x 1.4 ton/cu.yd. = a tons. <br /> F. ADSORPTION WIDTH <br /> Ahao faun math s 'ib>e <br /> 1. Percolation rate in top 12 inches of soil is 1c- mpi �-- W <br /> PeeadaMa.,h,,, peraq ..srr <br /> , Soil Texture <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 Coarse sand 1.20 1.00 <br /> 0.60 gpd/ft' 0.1 to Sand 120 1.00 <br /> 0.1 to 5 Fine Sand- 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 1.52 <br /> 3. Calculate adsorption width ratio b dividing rock laye 16 co 30 Loam 0.60 2.00 <br /> �' ' Y g Y 31 to 45 silt Loam OM 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 clay Loam 0.45 2.67 <br /> 1.20 d/ft2� 0.60 d/ft2 = 20 6erthan Clay 024 5_00 <br /> � � Slower than 120 Clay <br /> '•Soil having 501L or mare of fine=-very fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> a•0 x b ft ft <br />