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1998-010148 - new septic system
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1050 Tamarack Drive - 26-118-23-42-0006
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1998-010148 - new septic system
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Last modified
8/22/2023 4:18:51 PM
Creation date
4/16/2019 10:46:40 AM
Metadata
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Template:
x Address Old
House Number
1050
Street Name
Tamarack
Street Type
Drive
Address
1050 Tamarack Drive
Document Type
Septic
PIN
2611823420006
Supplemental fields
ProcessedPID
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MOUND DESIGN WORKSHEET <br /> ' (For Flows up to 1200 gpd) <br /> A. FLOW / s Fstirnatad Sew,aae Flog in Cellona per Day(Vd) <br /> Estimated 3o O gpd "t'gib" type i type It lYve 1„ TYpc ry <br /> or measured x 1.S = - gpd. Bedrooms <br /> 2 300 225 180 sow <br /> 3 450 300 218 <br /> B. SEPTIC TANK LIQUID VOLUMES 47600 iso 294 256 <br /> D,_/00 D gallons 6 900 525 332 <br /> 7 1030 600 370 <br /> 8 1200 675 408 <br /> C. SOILS(refer to site evaluation) <br /> r Ntaof y-rkTk <br /> 1. Depth to restricting layer= ►4s - a inches Beate0111 <br /> 2. Depth of percolation tests = 1 a '' inches <br /> 3. Percolation rate /o• a mpi 23 or 4 1'� 1 <br /> -100 <br /> 4. Land slope (o % 5 or b 2.000 2.000 <br /> 7 or a 2,000 3.000 <br /> over 9 See fa.C-6 (a 1.5) <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer.A x 0.83 - <br /> 3 coo . gpd x 0.83 sq.ft./gpd = L- ' sq. ft.i-)0'-o=d')4n <br /> 2. Select width of rock layer(10 feet or less) _ /0 ft. <br /> 3. Length of rock layer= area+width= Rock Bed <br /> sq. ft.+ )o ft. = a") ,.,.. .,.. .. .,.,.,,.. <br /> .%•�•1•I•I•I�•H�•IM•r•NH�M• <br /> ♦...ti.,=ti.�...�.ti.ti.,.ti.�.�.ti•ti kith 510 ft. <br /> • •I•r•f r•. t•/.r•r•HrM•t•. . <br /> '��--f-f-f-fti'ti�1;ti�--I f-fti f-f- <br /> E. ROCK VOLUME Length -� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> ;-)4 sq. ft. x 1,or ft. =Dald cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> a� cu.ft. +27=I-cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> I cu.yd. x 1.4 ton/cu. yd. =L tons. <br /> F. ADSORPTION WIDTH L�"'°�'`� x-01°'`''� Abmvdm WSdthstzln Lble <br /> I. Percolation rate in top 12 inches of soil is Jo. mpi reRaetion Rate C.0 <br /> minuin kch Soil Texture P'a'r <br /> (MOO ►.•�... ea. <br /> M <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand 1.20 1.00 <br /> .�-i.,L gpd/ft2 0.1 toy SandM 1.20 1.00 <br /> 0.1 to 5 Fine Sand 0.60 2.00 <br /> 6 to 15 Sandy Loam 0.79 132 <br /> 3. Calculate adsorption width ratio b dividin rock layer 16 to 3o Loam 0.50 2.00 <br /> rp � Y $ Y 31 to 45 Silt Loam 050 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; 46 to 60 Cls Loam 0.45 2.67 <br /> 1.20 d/ft2+ . d/ft2 = Slowerthan120 Clay 0 24 5.00 <br /> gP ��8P �-. <br /> -Soil ha"50%or mon d Cum or very fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> D_�x,)0_ft= aL.? ft <br />
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