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. �� . <br /> F-17 <br /> P3]MP SELECTION PROCEDURE <br /> Elq PERFORATWN OF A PERFORATED L4TERAL <br /> ' Determine pua�p capacity: o.�.�... <br /> ravity Distribution T....,, i � <br /> � 1 Minimum suoo�a�ted is 600 pallons�pr hour(10oTfm)to sta{�ahead of � �•��•-�--- <br /> OD�� O C� Or .J '.•G.:.,...... d G«Nnw�Faak(or rar• <br /> Wflt�f 11SE rdb2. ." �+aM f�M Ler.r� �;'�iw�.��a.w wwN <br /> 2 I' M a x imum sug,g�es t e d for de livery t o a dr op b o x o f a h o m e sys t e m i s 2,7 0 0 . ►-*ry��������^���h <br /> ��w�.., a. <br /> ' gallons per hour(45 gpm)to prevent build-up of pressure in drop box. �; � u�.„, ,r�e�,. <br /> :::;;.:.... <br /> d e«.ur« <br /> ... . . .... . hrhreMN LantN e� <br /> �essure Diatibution �: �,�,,.�.,.,,� ••��«►.�.�.� <br /> 3 �a. Select number of perforabed lateeals 3 <br /> b. Select perforation spacing= �_feet �.�,.'�"�.,'�""° <br /> r. Subtract 2 h.from t}�rock layer length. <br /> �-2 f�__,�fee� <br /> {i. Detennine the number of spaces between perforations. <br /> � I,ength p�f.spa�g=,�_ft.+�_ft.=J2 spaces Requi�ed peeioraeon Discha�e <br /> �• -1a-spaces+1=._1_�.Perfontions/lateral +n gallons Per aunute(&Pmf <br /> f. Multiply perforations per lateral by�umber of laterals to �!y�� '�e � ,�p,,,, ��d� <br /> �total number of perforations. ,�„�,� x ��-;�ei,=�perforations. �� 2 ' <br /> X��_-���,. <br /> 1.Oa 0.56 0.74 <br /> s�cr�°rv�c�Acm U�o gp� 2.Ob 0.80 1.04 <br /> B. etermine head reqnirtments: a.Use for single family homes <br /> 1. Devation difference�between pump and point of discharge. b.Use for all other applications <br /> �„�_feet <br /> 2. ! If pumping to a pressure distribution system,five feet for pressure <br /> required at manifold if gravity s tem,zero. <br /> S feet <br /> 3. Friction loss <br /> a. Enter friction loss table with gpm and pipe diameter. �P��B� <br /> Read hiction loss in feet per 100 feet from table: Poinc of D;scharBe <br /> � RL= . ` f�/100 ft of pipe �� <br /> b. Determine to�al pipe length from pump to discharge ���u;a,p;ff�,� <br /> I, point Add 25 peraent to pipe length for fitdng p�p �w� <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length-1.?S times pipe length= <br /> J x 1.25= f" � feet F-18b <br /> c. Calculate total friction loss mu1H 1 n 1.5 inch 2.0 inch 3.0 inch <br /> bY P Y� 8 gpR, �w�a.��aoa a a�a� <br /> friction loss in R/100 ft by equivalent pipe length. <br /> �' Total friction loss= � x L.a +100= feet 10 0.69 0.20 <br /> � �y -�-- i2 0.� o.2s <br /> �4. Total h�d required is the sum of elevarion difference, la 1.28 0.38 <br /> Special head requirements,and total friction loss. 16 1.63 0.48 <br /> 18 2.03 0.60 <br /> 20 247 0.73 0.11 <br /> � � +�_+�_ 2S 3.73 1.11 0.16 <br /> � (1) (2) (3c) 30 5.23 1.55 0.23 <br /> 35 7.90 2.06 0.30 <br /> 40 11.07 2.64 0.39 <br /> TOTAL HFAD � feet � 45 1a.73 3.28 0.48 <br /> 50 3.99 0.58 <br /> SS 4.76 0.70 <br /> �. I ump selection bo s.bo o.s2 <br /> 1. A pump must be selected to deliver at least <br /> �' <br /> gpm (Step A)with at least �- feet of total head(Step B). <br /> �I <br />