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. • MOUND DESIGN WORKSHEET 5 <br /> � � (For Flows up to 1200 gpd) <br /> A. �,QW Fstimaced Sewage Flows in Gallons per day <br /> d) <br /> Estimated 7�0 �C� Numbu Type I Typc Q Typc ID Type <br /> of IV <br /> or measured x 1.5 = gpd. <br /> z 3ao zis �so � <br /> B. SEPTIC TANK LIQUID VOLUMES a °6050o s30s° Zis6 °f'"� <br /> Zz�O gallons 6 'yo50o 'su s�z �,, <br /> � ioso � 3�o u« <br /> 8 IZ00 675 408 p1 <br /> C. SOILS(refer to site evaluation) `°''°"� <br /> 1. Depth to restricting layer= .�o inches .2 �z feet �` � �` <br /> ����r <br /> Num6er af Minimun liyuid . . n�adry wnA w�iN Aisposal& <br /> 2. Depth of percolation tests= /� inche �� �y �ds�� lihinsi0e <br /> 3. Texture 2ix1� '�o "u 's°° <br /> �lv,4.7'1 Percolation rate / 3 mpi ��R< i000 ,soo zaoo <br /> s�K� i soo zuo woo <br /> 4. Land slope % 7•A°�y Z� 3� � <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> 7S'D gpd x 0.83 sq. ft./gpd = Gz�sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') _ /c� ft. <br /> 3. Length of rock layer=area=width = ��•�Q��- A-Aa -..e � e e�aa-� <br /> . � �oa`'���`'�aKx <br /> (a��sq. ft. _ �ft. _�¢�ft. "`�°; ��° �.�� . ° <br /> �Qp'Q'°.bp.°.'&aoia-.m.�s-:ea.e:ae 0... <br /> a <br /> a o�: r e� G O A liU•Sb' f�:� <br /> .. .....o._ ,'e'p0"p'�"009.-�II. �u, <br /> Width�ft �d:�. o ::d .a ,ee . <br /> <120mpi <10' Length�ft <br /> E. ROCK VOLUME <br /> >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;�Z�sq. ft. x� <br /> ft. =f,�cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> (�Z.,cu. ft. -27= 23 cu.yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons;�cu. yd. x 1.4 � <br /> ton/cu. yd. _�tons. <br /> F. ABSORPTION WIDTH Absorption�dth Siang Table <br /> 1. Percolatio rate in top 12 inches of soil is�gnpi �.���� Sal Texam �� '�a e'�°° <br /> Texttue /1'1, cMpn �yuua�e�« ia,�«wam <br /> Fauer than 0.1 Coarae Smd 1.20 1.00 <br /> 0.1 to 5 Saod 1.20 1.00 <br /> 2. Select allowable soil loading rate from table; o.��s F,�s�a o.�o Z.00 <br /> 6 to 15 Saody l.oam 0.79 1.52 <br /> � �� gpd/ft� '-��3' s� o�. i.a.�.o' <br /> 46 to 60 Clay Losm 0.45 2.67 <br /> 60 to 120 Clay 0.24 5.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer s�o,v«w��zo c,sY o�0 6.00 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft�= ► � gpd/ft2= Z� O <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> .�_X�ft= �'v ft <br />