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1995-007008 - new septic system
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460 Sussex Lane - 04-117-23-31-0012
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1995-007008 - new septic system
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Last modified
8/22/2023 5:11:09 PM
Creation date
4/8/2019 1:34:03 PM
Metadata
Fields
Template:
x Address Old
House Number
460
Street Name
Sussex
Street Type
Lane
Address
460 Sussex La
Document Type
Septic
PIN
0411723310012
Supplemental fields
ProcessedPID
Updated
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MOUND DESIGN WORKSHEET <br /> � � (For Flows up to 1200 gpd) <br /> A. �.�w Estimsted Seavage Flow in Gallons per Day(gpd) <br /> Estimated�,�_gpd N`o� '[yp�1 'I�pe II Type III Type IV <br /> or measured = x 1.5 = - gpd. s��,� <br /> 2 300 225 180 �as <br /> 3 450 300 218 °t <br /> B. SII'TTC TANK LIQUID VOLUMES 4 �ao 3�s zs� .� <br /> s �so aso 2sa ;� <br /> I-�o1s0 �1'IDD �OI1$ 6 900 525 332 "'° <br /> 7 1�50 600 370 0�`� <br /> �� <br /> 8 1200 675 408 <br /> C. SOIIS (refer to site evaluation) � �� <br /> � ,� , i, N�bc y�7� �.�w <br /> 1. Depth to restricting layer = I -�� -N �-� inches B� �,, �,, <br /> 2. Depth of permlation tests = 1 a"�- l 4� �' inches `D"�' ``'�`' <br /> 3. PerCOlation rate �I. 7 mpi Lo�►`^ "To L�-��`-O�''''� Z3 a a� i'oso°o i:'so <br /> 4. Land slope (s % s a 6 t.soo z.uo <br /> �a s z,000 s.000 <br /> wc 9 Sce fig.C-6 (z 1.5) <br /> D. ROCK LAYER DIl�iINSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = <br /> �gpd x 0.83 sq. ft./gpd =��sq. ft.-�r►o`�_(��y , <br /> 2. Select width of rock layer(10 feet or less) = 1 D ft. <br /> 3. Length of rock layer = area=width = Rock Bed <br /> ��sq. ft.i �Q_ft. _�`�ft. ti.ti.ti.ti.,.�.ti•t•ti.1�ti•�1K ti•�•ti <br /> f.1.l.1•t.t•�r.f.�.f.l.j.J.f•j. <br /> - � � , ti•1•ti•ti•ti•1• �•ti�1•1•ti•t•�ti•ti•ti �dth 510 ft. <br /> . ' ' f.�•t•r•f•t�Y.f.r.l.t.f.f.j.f.r. <br /> ti•ti•ti•ti•ti•1•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti•ti • <br /> - ' r•t•t•l•l•t•r�.�t•r•r•J•fK•r•r• <br /> ti.L.ti.ti.ti•1.ti•ti•ti•�•ti�t•ti.ti•tiH•ti <br /> ,f.l.l•1•f•l.l•t.f.f.r.f.r.f.f.j. <br /> E. ROCK VOLUME �- �°g�' -� <br /> 1. Multiply rock area-b�r rock depth to,get cubic feet of rocic; <br /> i . . <br /> ���sq. ft. x ',ct � ft. _�.�cu. ft. , <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get_cubic yards; <br /> ��cu.ft. i 27=�2 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu. yd. x 1.4 ton/cu. yd. _ �� tons. <br /> F. ADSORP'1'ION WIDTH LL.�1-'� L.0�t�l A �w�a�,s�, Table <br /> 1. Percolation rate in top 12 inches of soil is �t, mpi peico]ationRahe ��, ;�„ <br /> M;,,ute,per;,�c.l, Soil Texture �.q,,.e �d,,,,, <br /> (mpil t a ,b.orwu. <br /> drh <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oarse Sand lzo i.00 <br /> d/ft� 0.1 to� Sand 1.20 1.00 <br /> •�S � 0.1 to� Fine Sand" 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1S2 <br /> 16 to 30 Loam 0.60 2.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer 31 to 45 si�c t.,oam 2.40 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to.�o c�a aoan, 0�44 s.00 <br /> 1.20 gpd/ft2�- .�1J/ gpd/ffi2= a-�, 7 . s�owe�t an�2o Ciay -- - <br /> "Soil haviag�09.or mare oE fine or vay fine sand <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �x_�_ft= al,.'? ft <br />
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