Laserfiche WebLink
� <br /> �lound Design Worksheet (For flows up to 1200 gpd) <br /> All boxed rectangles must be entered,the rest will be calculated. <br /> A. FLOW �A L Csti�riated Sev�age f lows in Gadons per Uv� � <br /> f�rumber of_....�_,,.._...._..T�,_........,,__.�_�.�r,._�......_._.. <br /> Estimated 900 gpd(see figure A-1) ' � <br /> or measured � x 1.5(safety factor)= 0 9Pd i bedrooiru � C�ass I i qoss II � (�ass IU� (�Ss IV <br /> E 2 ,�JJ � 2'1� 18J (rJJ�G <br /> B. SEPTIC TANK LIQUID VOLUMES i "� � d5J I �J9 218 � cf the <br /> Septic tank capacity 2-1300 gallons(see figure C-1) � '1 � ��� � 3r 15h � va�,es � <br /> , � ��J I 4�U ' �9� in the <br /> C. SOILS(Site evaluation dafa) � � +i `•`�� ' �`r� v�2 ��E, � <br /> 1. Depth to restricting layer- 1 feet � "1 ! IG�v� � 6�JJ � 310 � 8,0�11 <br /> 2. Depth of percolation tests= 12 inches ;......�.i_ I���p�.^.,�.47S,�,M, 4�NL J�� cc�r-ms.� <br /> 3. Texture Clay Loam <br /> 4. Soil loading rate(see Figure D-33) - 0.45 gpd/ft� <br /> Percolation rate 26 to 34 MPI <br /> 5. %Land Slope 1 % n:�:: .�i>�,►Nu����rtau�si����x�rr��i� <br /> P�'�rohnrn�Hate f.nud�ugka�c <br /> . . in 1,ti�ulcxr¢r So�1�C�ax:urc ! inilkmx ,1bs�x�on <br /> ��-�: :�@ �Et'Z��It�i('3 �l'IIItS(Ili YllttilS'1 9nr.h , i ncrc�:}•rcr ' Rcen <br /> - . ____.`�..�............1,_._ .._, �.�:'_trr loa �_�. <br /> t S <br /> 3.'l.�tFl�c C'il€)dbi��- � 1'�.u:•r�W�n 5 i (ner5=•tie�d i?U I lN) <br /> iVW11l°t:f i,t A'�i��t�lltil3 i.2c�';ic! � titlllll G3����11�'t�lll� � tit �,,,m ti:,n:i <br /> _ , t Ct'll�l tlitijh;)S�Ilt�. <br /> �3�GCCkS1.IS ��d�;d(.Si1'� �,3Y�):i�`l(�iS:3(�ti:Jx ' _ � 1 ��m:tiand <br /> ` �I�[1t151��C _., !�n �end - ---- <br /> _ _--- __. <br /> .. .... . r ta 15 .. �uJAd�.l.n�sp �� . �..Iq . _ I 4q <br /> .• . ^._ . �- _. .IG�uJO t I.oain !FL•fi._ ._�IN) ...-. <br /> L i;l'�C5S �� ���_` <br /> i`J" _ <br /> 1;;;;} :s�:o4< r ti�•r.t.�,���„ :;3ir zao <br /> ?t:l'�i 1 u:iJ i����J }•�y� 1 tisli . <br /> .^./;:[I G() E n Fi('tM.'�Aal �i 45. ..�.. �f) <br /> S til'{) ��i}:1 �.�11� ��:1'}I) �ti�t�}(7u�Lr,em <br /> :�itP�1 .'.{Irit{) ?��.�) n.��� : �,xy.i,�aut. <br /> .. .. . ... _ . . _ . � . ��.r. tn I?0 r �ilq�i lav - t�a� � ��":(tti-_ <br /> i 1 irtt�'�ia� <br /> .s- 1 I:g --- _ <br /> __ . . .. ._ ..__... .. ---- ._.... --___. <br /> Uc�c+�c�tltNri i'(1 � <br /> i t <br /> -.-srcr.i ekN-ac^fin 4�e:c uriSs muu re wJs« s y:mti,r.naiue <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow(A)by 0.83 to obtain required area of rock layer:Item A x 0.83= <br /> 900 gpd x 0.83 ft21gpd= 747.0 ft� <br /> 2. Determine rock layer width =0.83 ft�/gpd x Linear Loading Rate(LLR)(see LLR chart) <br /> 0.83ft�lgpd X 12 = 10.0 ft C1TY C)F ORC)NO <br /> SEPTIC PERMI P AN REV(EW <br /> LLRChart INSPF.CTOR �'1'��C��vw�+�. <br /> Perk Rate LLR DATE 9-Id,•0) PERMIT NO. <br /> � APPROVLD AS SliBMITTF.D <br /> <120 MPI <=�2 [� pPPROVED WITH C'ORRE.CTtnNS AS NOTBA <br /> >-120 MPI <-6 O NOT APPROVF.A-CORREC'T&RHSUBMIT <br /> These commeats uc Por your information. All work shalt be don� <br /> ia full complianso with ap applicable septic and xoaioY ewle. <br /> Requinment�it�cluding items twt speci�cally noted ia this ravisw. <br /> 3. Length of rock layer=area divided by width= x��Ttus rtrtK sBT ox stTE�t�tL T►MEs <br /> 747 ft� ! 10 feet= 75.0 feet <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by rock depth to get cubic feet of rock <br /> 747 X 1 ft= 750.0 ft3 <br /> 2. Divide ft3 by 27 ft3lyd3to get cubic yards <br /> 750.0 ft3 ! 27 = 27.8 yd3 <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> 27.8 yd3 X 1.4 tonlyd3 = 38.9 tons <br />