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2002-P05466 - new septic system
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525 Sussex Circle - 04-117-23-32-0012
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2002-P05466 - new septic system
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Last modified
8/22/2023 5:12:01 PM
Creation date
4/4/2019 12:41:50 PM
Metadata
Fields
Template:
x Address Old
House Number
525
Street Name
Sussex
Street Type
Circle
Address
525 Sussex Cir
Document Type
Septic
PIN
0411723320012
Supplemental fields
ProcessedPID
Updated
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F. ABSORPTION WIDTH <br /> 1. Abso tion width e uals absorption ratio(see Figure D-33)times rock layer width <br /> 2.67 x 10.0 ft = 27.0 ft <br /> G. MOUND SLOPE WIDTH&LENGTH(Greaterthan 1%) <br /> 1. Downslope absorption width=absorption width minus rock layer width <br /> 27 ,, feet - 10 feet= 17 feet <br /> 2. Calculate mound size <br /> UPSLOPE . <br /> a.Determine depth of clean sand at upslope edge of rock layer=3 feet minus distance to restricting layer(C1) <br /> 3 ft - 1.33 ft= 1.67 feet <br /> b.Mound height at the upslope edge of rock1ayer=depth of ciean sand for separation(G2a) <br /> at upslope edge plus depth of rock layer(1 foot)to depth of cover(1 foot) <br /> 1.67 R+1ft+1 ft= 3.67 feet <br /> c.Upslope berm multiplier based on land slo e(see 6gure D-34J <br /> Select benn multiplier of 3.12 <br /> d.Upslope width=berm multiplier(G2c)times upslope mound height(G2b): <br /> 3.12 x 3.5 ft = 10.9 feet <br /> I?-3�: S[..£)f'ls N6E1l;1'fP[.II?1i"1'hfii.Ii <br /> � E.and 1't'Si.!)PI� �[)C)�i"titiF OPF � <br /> Slu#rr multiplirrc fur�rrciou� ntai4}+IirF F�i�vuiaus <br /> InS�_ stop�ratlas ciapa rat3as <br /> 3:1 lsi 5�t � u,;,,i__,a__7:E„ Sit_ �3:i.,,..._4�1.S:t........_...Uc6��n7:6.,, <br /> 0 3.iP 4.0 S.Ei uA 7.6 s.a 3.a 4.@ 5.tk G.4 ?.4 <br /> 1 L4[ 3.$i �E.74 5.44 G.S•1 .'.4! 3.a4 i.t7 5.2l� 4,38 ?ad <br /> 2 �.$.? :i.,^•0 �i,5�i 5.3b 4.1•1 4.`JO 3..1? f�„35 5.�4+ U.b2 ti.C�4 <br /> J Y.:+3 3.57 �t3S S.Ek9 S.^'� ie.a5 3.:i4 6 rl aA8 ?..i2 BAtr <br /> 4 2.48 3:f:� 4.i' 4 6�1 5:Ifi U.06� 3.r9 i N.^!� G„2:� �,84 �D:r 2 <br /> 5 LA t 333 4.0� i.42 S.E9 �.^6 3.,5.'1 S.f14i U.tr7 S.S:' IO.Tr <br /> 6 L.Sd 3.23 3.95 �kr1 t ^t,n3 .*i.1 i 3.Lh 5.2b 7.f•7 4,36 12.(Yl <br /> 7 2.48 3.E2 3.^0 i.23 �f.'4 i_{3 b.8fl 5.,�41 ?.G'1 10.3•I 73.'3 <br /> 13 2:12 3.03 3.59 i.0'y 4.•i'X 4.A8 1.45 5.86 Ri.3] 11.5•1 Ir.9i <br /> 9 Y.3ti 2.9�1 3.15 3.�1f{ 4_1Q •t.65 4.6[ G.25 9.09 13.0�1 IN.92 <br /> 10 L1t 2.9ti 33.i 1.75 �.62 M1.;l�t 429 b.ti: IOAO 15A6 21.33 <br /> 11 ?,.Y4 2..'B 3.?.:s jbf ;<Y:i �.�b i.4M '.Zq ll.fl 1?.44 30.�.5 <br /> �x x.2� z.�u a.�z ►:�9 s.rw �t.�►b �r.c�q -.ti�► �xsct x1:u �s."s <br /> DOWNSLOPE <br /> e.Drop in elevation=rock layer width(D2)times percent landslope(C5)1100 <br /> 10 ft x 7 % !100= 0.7 feet <br /> f.Downslope mound height=depth of clean sand for slope difference(G2e) <br /> at downslope rock edge plus the mound height at the upslope edge of rock layer(2b) <br /> 0.70 ft + 3.67 R= 4.4 feet <br /> g.Downslope berm multiplier based on percent land slope(see Figure D-34) 5.56 <br /> h.Downslope width=downslope multiplier(G2g)times downslope mound height(G2fl <br /> 5.56 x 4.4 = 24.3 feet <br /> i.Select greater of G1 and G2h as the downslope width 24.3 feet <br /> j.Total mound width is the sum of upslope(G2d)width plus rock layer width(D2)plus downslope width(G2i) <br /> 10.9 ft+ 10.0 ft+ 24.3 ft= 45.2 feet <br />
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