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� ' PRESSURE DISTRIBUTION SYSTEM - Trenches
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<br /> All boxed rectangles must be entered,the rest will be calculated. �,��Q,r,,,•k
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<br /> 1. Select number of perforated laterals: �
<br /> . __........._.____.___....._...�_..--
<br /> 2. Select perforation spacing= �ft �E4;'NknkiiunoliciwdalenurtdxKuf 1/4-hcttpF!ricxotas
<br /> � pr„W knrd b pucsardao<l04L cAsctxxge vtu{nik�n
<br /> �..____....__..___.__.__.-�. ___._..
<br /> 3. Since perforations should not be placed closer that 1 foot to j"$`��;°,,�
<br /> the ed e of the rock la er see diag�am),subtract 2 feet from {__.__c����____t��_f� i ����x�,_���.s��,�:�, 2.0��.;►, .
<br /> 9 Y ( ,
<br /> the rock la er len th ; zs g ,n ,e 28
<br /> 63 -2ft= 61 ft i so � e � i3 _ n aa
<br /> rock layer length � ` a� 7 ,? ,s z
<br /> � so � a tC �a ..z
<br /> • �__�_._____.L.__.._ _______��.��..--
<br /> 4 Detennine the number of spaces between pertorations.
<br /> Divide the length(3)by perforation spacing (2)and round down to nearest whole number.
<br /> Perforation spacing= 61 ft/ 3 ft= 20 spaces
<br /> 5. Number of perforations is equal to one plus the number of pertoration spaces(4).
<br /> 'Check figure E-4 to assure the number of pe►forations per latera!guaranfees
<br /> < 10%discha�ye variation.
<br /> 20 spaces+ 1 = 21 perforations/lateral
<br /> 6. A.Total number of perforations=pertorations per Iateral(5)times number of laterals(1).
<br /> 21 perts/lat x 3 laterals= 63 perforations
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<br /> B. Calculate the square footage per perforation. �"� p�rforatiosi diameler
<br /> Should be 6-10 sqft/perf. Does not apply to at-grades. ir�ches
<br /> 1. Rock bed area=rock width(ft)x rock length(ft) �f�Q j �! 3,'�6 71�2 �14
<br /> 1 o ft x 63 ft= 630 ft2 �.p�+ p.�8 e.a2 0.5� 0.�4
<br /> 2. Square foot per perforation= Rock Bed Area/number of perfs(6)
<br /> 630.0 ft/ 63 perfs = 10.0 ft/perf 2��b ��26 Q•5Q Q.&0 j.04
<br /> 5.0 �.dl Q.94 i.2G 1.65
<br /> 7. Determine required flow rate by multiplying the total number -�„5.;,.;::,�,._,,«;�;,,;,;•=-��,r�����._f��•�.
<br /> of perforations(6A)by flow per ertorations(see figure E-6) °' `�.�f`.'''; , �s-•.
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<br /> 63 perfs x 0.74 gpm/perfs= 46.6 gpm
<br /> 8. If laterals are connected to header pipe as shown ', ,,.
<br /> in Figure E-1,to select minimum required lateral !��,
<br /> diameter,enter figure E-4 with perforation spacing(2)and � " ''•
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<br /> number of perforations per lateral(5). I '�" '
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<br /> I figwo E-�1:.ManHdd Loeatod at End of BVsfam �
<br /> __.._ .___- ._ ._._.___ _...---- ._._._ .. _.........._.___.�I
<br /> Select minimum diameter for perforated laterals= Dinches �
<br /> _....__ _--.__ _.._-- --._.- --- .._.�_
<br /> 9. If pertorated lateral system is attached to manifold pipe Fleure E 2 ManHofd LaocteC + fi�
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<br /> near the center, like Figure E-2, perforated lateral length(3) ` �`
<br /> and number of perforations per lateral(5)will be approximately 1 '
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<br /> one half of that in step 8. Using these values, select - � :;'�,_ ,;,:;.
<br /> minimum diameter for pertorated lateral= 1.25 inches. •
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<br /> I hereby certify that I have completed this work in accordance with all applicable ordinances, rules and laws.
<br /> (signature) �(�icense#) �lG 6�(date)
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