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04/21/1999 -letter re: Septic System Site Plan
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04/21/1999 -letter re: Septic System Site Plan
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Last modified
8/22/2023 3:22:12 PM
Creation date
3/27/2019 2:44:12 PM
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x Address Old
House Number
2120
Street Name
Carriage
Street Type
Lane
Address
2120 Carriage Lane
Document Type
Septic
PIN
1011723240036
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MOUNT) DES1(;N W'ol Kti IFi t <br /> Z-oi---- 5 <br /> (For Flows up to 120() gp(1) ////// -'^7 -5--;/---- <br /> iA. Fl.()\' I s Estimated Sewage Flows m Gallons p day <br /> Estimated - gpd Numbs 1 Type 1 131se 11, <br /> Type Ell ryM <br /> or measured x 1.5 =__ _ gpd- "' N <br /> 2 100 225 180~ ----. <br /> B. SEPTIC TANK LIQUID VOLUMES 4 450 100 218 <br /> 4 600 175 2566 <br /> olu <br /> 1 750 450 294 �'I e <br /> gallons 6 6 900 525 132 m <br /> 7 1050 1 600 170 til o1 <br /> or <br /> R 1200675 111 <br /> C. SOILS (refer to site evaluation) _ l I 40g �t� <br /> Salyut Tek` tt.vaults,1. Depth to restrictinglayer = �� inches 2-D feet <br /> LaqWa„p,L,,. <br /> Nuntxl ot Wert meas Lpad Irp.d p sy.,m '140.da,.... <br /> 2. Depth of percolation tests = /2- inches Caparaty gartmecm=om lih Laude <br /> 3. Texture ClAy loam Percolation rate /7-20 ' o 11001500 <br /> mpi t� X500 _� <br /> 5.,,n 1500 _250 <br /> 4. Land slope % 21 <br /> 7 Sc,..R..t 00 1030 ' <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> 7$ gpd x 0.83 sq. ft./gpd = 6 30 sq. ft. <br /> 2. Select width of rock layer (max 10' if <120 mpi max 5') = / v ft. <br /> 3. Length of rock layer = area —width = Q "`-4eA noeoo."1. an< ne f10op <br /> 6,.. .--) sq. ft. — /0 ft. = 63 ft. ua{oda nD D.;1Q:a F:Ana iter!la <br /> QrpD.pcbOnD n0 7jy n.-,z:0°Vb nO.Cu,7-al Cu d°.a..-Deer)i <br /> Width 10 ft :°eaeb. ..ebOaoAe�oa aD aoo„e.,oa ez <br /> <120mpi <10' Length. Ds— ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; 63) sq. ft. x t <br /> ft. =430 cu. ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> 63) cu. ft. _ 27 = 73 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get wei ht of rock in tons; cu. yd. x 1.4 <br /> ton/cu. yd. = tons. <br /> F. ABSORPTION WIDTH Absorption Width Sizing Table <br /> 1. Percolation rate in top12 inches of soil is `I s-6� <br /> /��`// mpi Percdanoo Rate in Gallons Rano of Absapoon <br /> Texture C V t. ((re•E` Minutes pa inch Soil Texture pa day per width to Rock <br /> (MPF) square foot Layer Width <br /> Faster than 0 1 Coarse Sand 120 1 00 <br /> 00 <br /> 2. Select allowable soil loading rate from table; 0�to hoc Sand d 060 2 00 <br /> 2 <br /> 6tSand 00 ' `i5 rd/ft` 1 �0 60 z a <br /> 31 to 45 Sdt Loam 0 50 2 40 <br /> 46 to 60 Clay Loam 0 45 2 67 <br /> 60 to 120 Clay 0 24 --5-m' <br /> 3_ Calculate adsorption width ratio by dividing rock laver Slow,than 120 Clay 0.0 6 W <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft'= gpd/ft2 = . 2,67 . <br /> 4 Multiply adsorption width ratio t)v ruck layer width to get <br /> required adsorption width; <br /> 2-62__ x (O ft = 24-7 ft <br />
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