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I' 17 <br /> 1'I JMP S ELI CTTONJ JiO CW URI: <br /> UO PEREORAT ION Of A PT RI-ORATED LATERAL <br /> A. Determine pump capacity. -w,,,�.. <br /> 0, <br /> Gravity Distribution 1 a. y <br /> 1 Minimum suggested is 600 gallons per hour(10 gpm) to stay ahead of - "+:,,:` <br /> •--l « 1.G....,W tar Is. <br /> water use rate. • lam,.50.0,l..era.a hay. „,,a..,,,, <br /> 1,,a r.a 0, <br /> 2. Maximum suggested for delivery to a drop box of a home system is 2,700 tip ,T. ,11 Ra.r.ar,la,l, <br /> gallons per hour(45 gpm)to prevent build-up of pressure in drop box. no :, 12.,0 Efte <br /> -P`rNrell..local.d al <br /> Pressure Distibution c,aa„Sane serer. e.11era«Lalerai <br /> 3.a. Select number of perforated laterals <br /> b. Select perforation spacing= feet 1 .M <br /> .I. I Sell .,.aer,y S.a,llaa <br /> e«an Pbop Send Layer <br /> C. Subtract 2 ft. from the rock layer length. <br /> 2 ft.= feet <br /> Rakd. Determine the number of spaces between perforations. <br /> Length perf.spacing= ft.+ ft.= spacesuired Perforation e <br /> e. spaces+ 1 = perforations/lateral in gallons per minute <br /> f. Multiply <br /> total]n ember of per <br /> lateral by number of laterals to Discharge dge 752."Pte/ Ind a,( <br /> gepe 4-;.,=--.i. X p.,,„n„a.,- perforations. (feet) <br /> g- x um,perf- gPm- <br /> 1.0a 0.56 0.74 <br /> SELECTED PUMP CAPACITY L/7gpm 2.O1J 0.80 1.04 <br /> B.Determine head requirements: a.Use for single family homes <br /> 1. Elevation difference between pump and point of discharge. b.Use for all other applications <br /> ) Z feet <br /> 2. If pumping to a pressure distribution system,five feet for pressure <br /> required at manifold if gravity s tem,zero. <br /> feet <br /> 3. Friction loss <br /> a. Enter friction loss table with gpm and pipe diameter. Pipe Length <br /> Read friction loss in feet per 100 feet from table. 1 t <br /> F.L= /60 ft/100 ft of pipe Point of Discharge <br /> b. Determine total pipe length from pump to discharge Elevation Difference' <br /> point Add 25 percent to pipe length for fitting <br /> Pump 1 <br /> loss,or use a fitting loss chart. Equivalent pipe <br /> length-1.25 times pipe length- <br /> F-18b <br /> /CIO x 1.25 = 1 feet <br /> c. Calculate total friction loss by multiplying 1: ch 2-0 inch 3.0 inch <br /> an', <br /> � lea per 100 ft of pipe <br /> friction loss in ft/100 ft 1).y equivalent pipe length_ <br /> Totalfriction loss= I, Z5-- x 3. 28 +100 `/= 7,0 feet 10 0.96 0.28 <br /> 4. Total head required is the sum of elevation difference, 14 1028 0 38 <br /> 14 1.28 0.38 <br /> special head requirements,and total friction loss. 16 1.63 0.48 <br /> 18 203 0.60 <br /> 20 2.47 0-73 0.11 <br /> - -- + 25 3.73 1 11 0.16 <br /> (1) (2) (3c) 30 S 2; 1.55 0.23 <br /> 35 7.90 2-Ot, 0.30 <br /> TOTAL HEAD . 2 / _- 4S feet •is 1a4 126 0.39 <br /> 74 3?8 048 <br /> 50 1 99 0.58 <br /> C. Pump selection _611 S70 0.70 J <br /> 6s.6(1 v-sz <br /> • <br /> I <br /> 1. A pump must be selected to deliver at least <br /> �� gpm (Step A) with at least Zi feel of total head (Step fl)_ <br /> 1 <br />