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5 <br /> MOUND DESIGN WORKS111:1-1 Gk%'W` ie___ S•% <br /> (For Flows 1111 to 1200 gpd) <br /> iA. Fl.OW I 1slimated Sewage Flows in Gallons per day <br /> Estimated /� 7 gpd I Numtrr ITypc I Tyne LI Type pl 7ya <br /> or measured x 1.5 gpd. "' (` <br /> 2 100 225 180 <br /> B. SEPTIC TANK LIQUID VOLUMES 4 601 600 375 216 ftb <br /> 0 175 256 of the <br /> valuta <br /> o� -/3'"b gallons 16 I 525 ;32 I 1 ype l <br /> 7 ' 1050 I 600 170 <br /> 8 1200 675 408 �n <br /> C. SOILS (refer to site evaluation) ��+umns <br /> tiytx Task Gpoar.e tm Lkaumi <br /> 1. Depth to restricting layer = o2"/ inches 20 feet liquid capac„y <br /> Numhcr of M nr nos Lapubd lid c+t"'ary wM wN du oj& <br /> 2. Depth of percolation tests = /7-. inches Bodn•.mu sats gar6.ac&slow Id,out c <br /> 3. Texturei/4 /C 1 Percolation rate /7-ze2 ...tet '0 '123 ;500 <br /> mpi �,.. t0oo ,3� .000 <br /> 5... 1300 2230 <br /> 4. Land slope c/ °/O yam4000 <br /> ° <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: A x 0.83 = <br /> 750 gpd x 0.83 sq. ft./gpd = 43v sq. ft. <br /> 2. Select width of rock layer (max 10' if<120 mpi max 5') = /0 ft. <br /> 3. Length of rock layer = area - width = <br /> 630 sq. ft. ÷ / 1r7� '.11.(=� ° �1 a u o <br /> [D ft. = D 3 ft. d-/' af) D dpo.E Q� !I fi°•,. ',.,tit <br /> «_ .�OOpwOpnD nD yD,n-ci.0° d.vp 0°.n d°d°.cz -i.�oi <br /> Width /0 ft --ao oea..►eQDe�'"D aD,00r ai <br /> <120mpi <10' Length i3__ft <br /> E. ROCK VOLUME >120mpi <5' <br /> 1. Multiply rock area by rock depth to get cubic feet of rock;430 sq. ft. x I <br /> ft. =e ) Cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> 636 cu. ft. - 27= 2 3 cu. yd. <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; cu. yd. x 1.4 <br /> ton/cu. yd. = ?3 tons. <br /> F. ABSORPTION WIDTH Absorption width Sizing Table <br /> 1. Percolation rate in top 12 inches of soil is3-415-Tnpi FkrcolanonRate In Gallows Rano ofAbsorptton <br /> Minutes per inch Soil Texture per day per width w Rock <br /> Texture5�/���'c/�1 <br /> (MPt) square foot Layer Width <br /> Faster than 0.1 Coarse Sand 1 20 100 <br /> 2. Select allowable soil loading rate from table; o 1 to 5 Flea and 060 2 00 <br /> G •5- gpd/ft_2 61015 Sandy Loam 060 200 <br /> 16 t taw Loan 0 60 x1 <br /> 31.aA5_ Silt Loam 0.50 240 <br /> -46 to 60 Clay Loans 0 45 2.67 <br /> 60 to 120 Clay 024 500 <br /> 3. Calculate adsorption width ratio by dividing rock laver Sloven.than 120 Clay 020 6(X) <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; <br /> 1.20 gpd/ft2= gpd/ft2 = . <br /> -1 Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> 2x /o ft = p2X0ft <br />