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1994-006508 - septic system
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605 Stubbs Bay Road North - 32-118-23-21-0005
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1994-006508 - septic system
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Last modified
8/22/2023 4:39:27 PM
Creation date
3/20/2019 2:23:19 PM
Metadata
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Template:
x Address Old
House Number
605
Street Name
Stubbs Bay
Street Type
Road
Street Direction
North
Address
605 Stubbs Bay Road North
Document Type
Septic
PIN
3211823210005
Supplemental fields
ProcessedPID
Updated
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' � MOUND DESIGN WORKSHEET <br /> � (For Flows up to 1200 gpd) <br /> . � y <br /> A. FI'OW 8ctimated Sewage Flows in Cdlonc pe day <br /> Estimated y.SC� gpd (see pages D-7 or I-3,4,5) � . <br /> or measured _ - gpd x 1.5 = -- R��� �Ya�I ��� '�Yr���� � �� <br /> B. SEPTTC TANK LIQUID VOLLJMES 3 4s00o 3a�o ii°a � <br /> � a bao s7s 2s6 .�,�. <br /> � - 1�c� c� gallons (see pages C-3 or G5) s �s� as� z� e <br /> 6 900 525 332 '�1. <br /> 7 1050 600 370 � <br /> C. SOILS (refer to site evaluation) g "A° 6's °o� °°'"' <br /> 1. Depth to restricting layer= �a��ru 30 �� inches ��""kc.�"'�,w•."�,,. <br /> � - /� Number o( MinLoum Uquid Liquid ap�ciry�riih <br /> 2. Depth of percolation tests = I� inches o�• c.o.�� �..�d�.�.., <br /> 3. Percolation rate �,.� mpi z3�� � �� <br /> 4. Land slope � % ,'e a 9 � � <br /> mx 9 »r. <br /> D. ROCK LAYER DIMENSIONS <br /> 1. MulHply flow rate by 0.83 to obtain required area of rock <br /> layer: Daily Flow x 0.83 = � <br /> _c _-�v_gpd x 0.83 sq. ft./gpd = �sq. ft-►�1��'�u= 4 ►v" <br /> 2. Select width of rock layer (10 feet or less) _ /c� ft. <br /> 3. Length of rock layer = Area+Width = <br /> � � sq. f t. + 1 c .f t. _ � I f t. Rock Bed <br /> f•t•r•I•t•t•t•t t•l.!•t•l.l•t <br /> ti'ti•ti•ti•'L•ti•ti�ti•�•ti••.•ti•ti ti ti <br /> l t•t•l•l.t•�'•I'.l•��t t•l.l•f <br /> • •i•t•ti•ti•ti•�•�••.•ti.ti.ti•ti.ti•ti•ti. idth 510 ft. <br /> �•t•l.r.f.f.f.;.J.l•t 1•r•l•t <br /> E. ROCK VOLUME '•��•�•�•�.•.�•L•ti•~•~•ti•~•1• <br /> f.,.r.f.f.f.f.�.f.f.f.f.f.f.f 1 ' <br /> � Length <br /> 1. Mi�ltiply rock area by rock depth to get cubic feet of rock; <br /> r; sq. ft. x i.:•.� ft. _ �o cu. ft. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yards; <br /> � ,-- � cu. ft. +27 = 11�cu. yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> J� cu. yd. x 1.4 ton/cu. yd. = :�:� tons. <br /> F. ADSORPTION WIDTH � -�+ � � � �"���� � <br /> 1. Percolation rate in top 12 inches of soil is �- •� m�71 Absorplion W(JthSlzl�gToblc <br /> Pereoledon Raic G�Ilons Ratio of <br /> 2. Select allowable soil loading rate from table on page E-; inMinuletpu SoiiTeamrc perdoyper Absorptimwidih <br /> , i (nch(MPl) uare foa Io Nock Ln er <br /> ,`_' '� gPd�f� '� w���n y <br /> 3. Calculate adsorption width ratio by dividing rock layer Faeterll�en0.1• c�.�so�e ..__ _.._ <br /> 0.1 w S Sand 1.20 1.00 <br /> loading rate of 1.20 gpd/ft�by allowable soil loading rate; o.�►�s•• FineSand�• o.�o z.�o <br /> 1.20 d/ft2+ . � � d itZ= ,� . 6 to 15 s��aY u,.m o.�s �.sz <br /> gP �P / _. l-, 1 �b�o:�o �.m o.�o z.� <br /> 31 l0 45 Sllc I,oem 0.50 2.�0 <br /> Check this value on page E-16. . a6�o�► c�.y� o.4s z.F� <br /> 60 w 120 Cley 0.24 S.W <br /> 4. Multiply adsorption width ratio by rock layer width ko get 5���;;;r^ c�.Y ___. __. <br /> required adsorprion width; <br /> � !-'i x 1�� f t - .:;r.. 'J f t <br /> � <br />
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