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2003-P06517 - new septic system
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585 Stubbs Road North - 32-118-23-24-0006
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2003-P06517 - new septic system
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Last modified
8/22/2023 4:40:02 PM
Creation date
3/20/2019 2:07:13 PM
Metadata
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Template:
x Address Old
House Number
585
Street Name
Stubbs Bay
Street Type
Road
Street Direction
North
Address
585 Stubbs Bay Road North
Document Type
Septic
PIN
3211823240006
Supplemental fields
ProcessedPID
Updated
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. • MOUND DESIGN WORKSHEET (For nows up to �200 gpd) <br /> A. Es4imated 600 pd or measured X 1.5 = gpd <br /> B. SEPTlC TANK LIQUID VOLUMES: 2000 <br /> C. SITE EVALUATiON INFORNiATION <br /> 9. Depth of clean sand req. 18.OQ inches or 1.50 feet <br /> 2. Depth of percolation tests = 12 inct►es <br /> 3. Soi! Texture Silt Loam <br /> 4. Perc. Rate 29 mpi <br /> 5. l.and Slope 8.0 percent <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock layer: <br /> 600 gpd X 0.83 sq ft/gpd 498.00 sq. ft. rock area <br /> 2. Select width of rock tayer �Max �o� ���2a, or ma�c s�irt>�20} 10.0 eet <br /> 3. Rockbed length ��r,� 498.00 sq. ft. / 10.0 feet = 49_8 feet <br /> Round off 50 <br /> E. ROCK VOLUME <br /> 1. Multiply rock area by a�ock depth to get cubic feet of rock: <br /> 498 sq. ft X 1.0 = foot = 498 cubic feet <br /> 2. Divide cubic feet by 27 to get cubic yards: <br /> 498 cu. ft. ! 27 = 18.4 cubic yards <br /> 3. Multipfy cubic yards by 1.4 to get weight of rock in tons: <br /> 18.4 cu. yd. X 1.4 = 25.8 tons X 10 % = 28.4 tons req'd <br /> F. ADSORPTlQN WIDTH <br /> 1. Percolation rate in to 12 inches of soil is 28.0 mpi <br /> Soil Texture is iit l.oam <br /> 2. Select allowable soil ioadi�g rate from table: 0.50 pd /sq. ft. <br /> PEC RA E GPD J .FT RATIO <br /> A > .1 1.20 1. <br /> 0.1 TO 6 SAND 1.20 t.00 <br /> 0.1 TO 5 fNE SAND 0.90 2.00 <br /> E TO 15 9ANOY LOAM 0.79 1.bY <br /> 16 Tp 30 LOJ1M 0.80 2.� <br /> 31 TO 46 81LT IOAM O.bO 2.10 <br /> 18 TO e0 CLAV IOAM D.4b 4.E7 <br /> 8�TO i20 CLAV 0.21 5.00 <br /> >120 CLAV 0.20 B.DO <br /> 3. Calculate adsorption width ratio by dividing rock iayer loading rate <br /> of 1.20 gpd /sq. ft. by allowable soil loading rate: <br /> 1.20 gpd!sq. divided by 0.50 gpd /sq. ft. equals 2.40 <br /> 4. Multipty adsorption width ratio by rock layer width to get Eequired adsorption width: <br /> 2.40 X 10.0 feet = 24.0 feet adsorption width <br /> PAGE 4 OF 12 <br />
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