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. E-ly <br /> ' , ' , MOUND DESIGN WORKSHEEI' <br /> (For Flows up to 1200 gpd) � . .. __.. ' . <br /> �' .�. e,.,.FLOW . ' • D-7 ' <br /> .'� • ' ��;:stimated �5� gpd (see pages �-7 or I-3 4 5) a"�"m'""��°"�°��°� <br /> � � r�a tnri s owwcc� <br /> or measured gpd. °�"°°'° _ ° � a <br /> f 700 ti! iq � <br /> 1 YO 700 fl• � <br /> • �00 37! bt """` <br /> B. SEPTTC TAIVK LIQUID VOLUMES <br /> � t00 W �Sf ++,L <br /> � I000 �00 �7'0 ~ <br /> �, )nc�o gallons (see pages C-3 or C-5) � �� � �« �- <br /> , � _�_ . <br /> � � C-3 <br /> C. S�R$ (IP.fET f0 SIt2 2S�dIL13t10I1� wrK T�wc ur,�cnus, w a►«oNs <br /> 1. Depth to restricting layer= )� inches '�--'d � `='�� <br /> soo� uae eu�an Nwo�u <br /> 2. Depth of percolation tests = I a inches ,,,,,. ,.. ,,,. <br /> 3. Percolation nte ���� mpi '�.�r �,a :'— '°'• ,••: ,••• <br /> • 4. Land slope � � o %'o •�• ,••• "•• <br /> ��a� �... �... <br /> � <br /> D. ROCK LAYER DIMINSIONS <br /> 1. ' Multiply flow rate by 0.83 to obtain required area of rock '__ <br /> r <br /> layer: A x 0.83 = \ w <br /> usa gpd x 0. 3 sq. ft./gpd = � S�sq. ft. � <br /> 2. Select width of rock layer (IO feet or less) = i 0 ft. ` <br /> 3. Length of rock layer = area+width= <br /> � So sq. ft.+ ,�_ft. _�ft. Rock Eed <br /> � f.,.,.;.�.,.,.,...,.,.,.,.... <br /> :...� .�...�..., ,.,.,.,.�.�. <br /> � f''''''"'''''''''''''''''''' <br /> ti•�•�.�•�•�•�•ti.� `•�•ti.�.�•�• dth S20 ft <br /> �.f•r•i•i•r•r•�•i•i•�•r•r•�•♦ <br /> ti•�.�•�.ti•ti.�•�•� �.�•�•�•�•�• <br /> .��f�f.�./.�.��/��.�.j�I.��1�1 <br /> � E. ROCK VOLUME �— �-�+s� —� <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> � �) Sbsq. ft.x�ft. =�-,�5 cu.ft. <br /> 2. Divide cu. ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> L�,�cu. ft. +27=�cu.yd. : <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; � <br /> l�cu.yd. x 1.4 ton/cu. yd. = 3. tons. <br /> � <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is�I �� mpi E-16 <br /> 2. Select allowable soil loadin rate from table on page E-16; •�•�-����d��� <br /> gpd�ft2 ►--�- �--�-•_ <br /> 3. Calculate adsorption width ratio by dividing rock layer '"" `"" `"" """ ""r`"'�" <br /> • loading rate of 1.20 gpd/ft2 by allowable soil loading rate; ���� � �� �� ��~ � ��~ <br /> . ... ..,. .�. ..., �... <br /> �• .1� �.N �1� �.N �.M <br /> f� .H �.M �I� !.Y 1.�� <br /> � � y� �� �d _ .. ... .... ..,, ,..� .... <br /> 1.20 d it2 /ft2= I � . ., .,�. .�. .•. .... .... <br /> Check this value on page E-16. ' <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br />`� � I , S x 1 o ft =�5 ft , <br /> � . <br /> : : <br /> J . <br />