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2004-P08027 - new septic
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440 Stubbs Bay Road North - 32-118-23-13-0006
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2004-P08027 - new septic
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Last modified
8/22/2023 4:39:24 PM
Creation date
3/20/2019 12:43:31 PM
Metadata
Fields
Template:
x Address Old
House Number
440
Street Name
Stubbs Bay
Street Type
Road
Street Direction
North
Address
440 Stubbs Bay Road North
Document Type
Septic
PIN
3211823130006
Supplemental fields
ProcessedPID
Updated
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07/21/2064 14:01 3202382343 HENTGES PAGE 06/14 <br /> MQUND DESIGN WORKSH��T (Forflows up ta 9200 gpd) <br /> A. Estimafied T50 pd or msasured � X 1.5 = gpd <br /> B. SEPtiC TANK LIQUID V4LUMES: 2250 <br /> C. S�TE EVALUATION INFORAAATI�N <br /> 1. Depfh of cle�n sand req. 16_00 inches or 1.5Q feet <br /> 2. Depth of percalation tests = 12 inches <br /> 3. Soil Texture Silt Loam <br /> 4. Perc. Rate 29 � mpi <br /> 5. Land Slape 5.0 percent <br /> D. ROCK LAYER DlMENSIONS <br /> 1. Multiply flow r�te by 0.83 t� obtain required area of rock layer: <br /> 750 gpd X 0.83 sq ft/gpd 622.50 sq. ft. rock area <br /> �. SeEect width of rock layer (Max 10' if�120, or max 5' if>12p) 10.0 8�9t <br /> 3. Rockbed length ��„,;atn� 622.5Q sq. it. / 10.0 foet = 62.3 fest <br /> Round off �3 <br /> E. ROCK VQLUME <br /> 1. Multiply rock �rea by rock depth to get cubic feet of rock: <br /> 622.5 sq. ft X 1_Q = foot = 623 cubic feet <br /> 2. Divide cubic feet by 27 to get cubic yards: • <br /> B23 cu. ft. / 27 = 23.1 cubic yards <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons: <br /> 23.1 �u. yd. X 1.A = _ 32.3 tans X 10 °/a = 35.5 tons req'd <br /> F. ADSOR�'TIQN WiDTH <br /> 9. Percolation rate in ta 12 inches af sail is 28.0 mpi <br /> Soit Texture is Silt Loam � <br /> 2. Select allowable soil loading rate from table: 0.50 pd / sq. ft. <br /> �MP� a��xru e P �6a,Fr. w�no <br /> ► . Rs s�rto �.ao +, <br /> O.t Tp 6 SANQ 1.Z0 t.0p <br /> O-1 TD 6 FINE 9AND 0.80 2,On <br /> 6 7016 SANDY LOAM 0.79 1.bZ <br /> 16 TO�0 LOAM 0.66 2.06 <br /> a1 TO46 SILTLOAM 0.50 Z.40 <br /> d6'TO e0 CLAV�pAM 0.45 2.87 <br /> 8D TD 12o CtAY 0.24 6.00 <br /> �120 CLAY 0.2Q 8.00 <br /> 3. Calculate adsorption width ratio by dividing rock layer loading r�te <br /> of 1.20 gpd /sq. ft. by a�llows�ble sqif Ipading rate: <br /> 1.20 gpd/sq. divided by 0.50 gpd /sq, ft. equals 2.40 <br /> 4. Multiply adsorption width ratio by rock I�yer width to get required adsorption width: <br /> 2.40 X 10.0 feet = 24.Q feet adsorption width <br /> PAGE 4 OF 92 <br />
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