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s� � Job#� <br /> T�wrir�rr <br /> Pwooww�r <br /> Universi� of Minnesata Mound Design Worksheet <br /> ���x� <br /> a �ow <br /> Estirrialed � soo gpd(9ee fgu�A-1) - ( <br /> or meee�ired x 1.5(safetY fac�o�- i 0 gpd <br /> B. �P'iIC TAlqC LIQUID VOLUMES <br /> Seplic tank qpecity 2000 galbns(see figure G1) <br /> t�xr�er d tankslcompar6nents 0 <br /> Efl�ent Fil� (Y�) Y� <br /> C-1 Seplk Tank k�Gallons <br /> Nianber of M'mimum Capaary with Capaaty witl� <br /> Bedrooms Capacily Garb.Disp. Disp.and lift <br /> or less 11 5 <br /> 3 or 4 1500 <br /> 5 or 6 7150 <br /> 7,8 or 9 3000 <br /> C. SOL.S(Sife ev�ua6on data) <br /> 1. Depth b resUiding layer= 2.1 feet <br /> 2. Deplh af penoolation tests= 12 inches <br /> 3. Te�xe bam <br /> 4. Sai loading ra�e(see Fgima D-33) 0.60 9pd�� <br /> P�eroolation rate 3 MPI <br /> 5. 96 Land Sbpe 6.0 % <br /> D. ROCK LAYER O�IENSIONS <br /> 1. Multiplp aver'age d�ign flow(A)bY 0.83 t�ob�ain req�ed are�a d rodc la�r:I�m A x 0.83= <br /> 600 gpd x 0.83 il�k,�pd= 500 ft� <br /> 2. O�e rock layer widlh =0.83 il`Igpd x L.inear Loa�ng Ra�e(LiR)(see LLR d�art <br /> 0.83 it�/gpd x 12.00 = 10.0 ft <br /> LLR Chxt <br /> Perk Rabe LLR <br /> <120 MPI <=12 <br /> >=120 MPI <� <br /> 3. l..englh of rock layer=area divided by wi�h= <br /> 500.0 1t� / 10.0 feet= 50.0 ft <br /> E ROCK VOLUII� <br /> 1. I�ddpyr rodc�a by rodc depth to g�a�bic feet of rock <br /> 500.0 X 1.0 ft= 500.0 ft3 <br /> 2. Divide iC�by 27 it�tyd3 to get cubic yards <br /> 500.0 ft3 / 27 = 18.5 yd3 <br /> 3. Nhd6ply cubic y�by 1.4 to get weight d rodc in 1ons; <br /> 18.5 yd3 X 1.4 ta�yd3 = 25.9 tons <br /> Page 1 of 5 <br />