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• • t-ly <br /> ' MOUND DESiGtV WORKSHFET <br /> (For Flows up to 1200 gpd) <br /> A. FLOW D�� � <br /> �_gP p g A ESIWtFF�SCw�GC ROwl iN ULLOtit.f71�.. <br /> � fl <br /> Estimated O d �$� a es D-7 or I-3�Y� 5� �� r.� or acs�ov.cc° � <br /> or measured gpd. �°"°°� _ � II s <br /> 2 - � �� ,.� .ox <br /> 3 .70 30o ti. a, <br /> • {00 ]7� � •aw <br /> B. SEPTIC TANK LIQLJID VOLUMES : ,'o �n ;;� '�.` <br /> Z—/O D O �allons (see pages C-3 or C-5) ' �� � 37� <br /> e i zoo s» .o� c�.. <br /> C-3 <br /> SEPTIC T�HK CAVACITES, IN GALlONS <br /> C. SOILS (refer to site evaluation <br /> 1. Depth to restricting layer = i�$ inches "'�"�`.��`m <br /> Ma��O I��W{IY MIMO�N�Uf <br /> YDMOY! UOUN CU�UT� 0�lIO��I <br /> 2. Depth of percolarion tests = /2 inches ,a,,,. ,., ,,,, <br /> 3. Percolarion rate 2 O mpi ��� �••� ,,•a <br /> �a�� i�ae �t�a <br /> 4. Land slope_, �_°'o ,.�a� <br /> ,.e. �.00 <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer: A x 0.83 = <br /> Sb gpd x 0.83 sq. ft./gpd =•3�-3 sq. ft. <br /> 2. Select width of rock layer (10 feet or less) _ /O ft. <br /> 3. Length of rock layer = area i width = I <br /> 3 73_sq. ft. y /o ft. = 3 7 ft. Rock Bed <br /> f•f.r.I•f.f•f.t•f•t•f•I•l.t•tT <br /> ti•ti•5�•ti•ti•5�•ti•t•L•�•ti•ti•ti•ti•L• I i <br /> � tiftifti�ti�ti�ti:ti��f'Lfti�tif~1tif�ftif idth Sl� <br /> t•t•l•l•r•f•f•t�I•�'•t•r•r.f•t <br /> ~f�f�f~f�f�f�f�f�f�f�f�f�f�f�f 1 <br /> E. ROCK VOLUME �-- Le��,--� I <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; <br /> 3 7�3 sq. ft. x�f t. =3 73 cu. f t. <br /> 2. Divide cu. ft. by 27 cu. ft./cu. yd. to get cubic yazds; <br /> 373 cu. ft. 127= /`� cu. yd. <br /> 3. Multipl cubic yards by 1.4 to get weight of rock in tons; � <br /> .,/� cu. yd. x I.4 ton/cu. yd. = Y�tons. � <br /> F. ADSORPTION WIDTH <br /> 1. Percolation rate in top 12 inches of soil is 2o mpi E-16 <br /> 2. Select allowable soi� loading rate from table on page E-16� �++D'+�a+�aaetin�awuuwoarcu.oe � <br /> , c� gpd/f t2 :..d.� .r...,...,.M� —I I <br /> ,.,. �.-��.� <br /> 3. Calculate adsorFtion width ratio by divi ding roc k layer '""" "'"'� `�" " " = � <br /> •n� � �.ae �.ea �.a �eo � <br /> l�adir.� rate of 1.2n �pd/ft2 by allowable soil loading rate; • " °" '" "' "' <br /> ,. �a ..� o... .... .oa- <br /> f� .�� e.�e a.w reo f..a <br /> 1.�� gpc!/ft?_y _�loo gpd/ft2 = 2 •o v •• .•� ^.• _,_ •� � _•, ' <br /> -- ., .,t, a t. o.,. ... �o0 <br /> Cherk this value nn page E-16. ' <br /> 4. Multipiy adsorption width ratio by rock layer width to get � <br /> required adsorption width; � <br /> __Z x� ft = Zo ft � <br />