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� ' MOUND DESIGN WORKSHEET <br /> � � (For Flows up to 1200 gpd) <br /> A. FLOW Estima►ed Seva`e Flow�u�Gallons pa DaY(� <br /> FS�ldtE'd LOO �d N�anber <br /> or measured — x 1.5 = — gpd. �'�� n'p`J �Ya�II �ur �ty�rv <br /> z soo us �so � <br /> 3 450 300 218 � <br /> B. SII'TIC TANK LIQUID VOLUMES � + � s�s zs� ,,,,e <br /> 5 750 450 294 b <br /> �— /O t�O g3llOI1S 6 900 525 332 � <br /> 7 1050 600 370 � <br /> $ 1200 675 106 <br /> C. SOILS(refer to site evaluation) ,,` �w <br /> 1. Depth to restricting layer= aT� 3 s� inches N& °m� �, ;,� <br /> 2 Depth of percolation tests = inches `'""0 `'"""' <br /> 3. Percolation rate /o. � mpi 2i«i" �'.0500o i',s o <br /> 4. Land slope 5 % i a a lzo�'oo s,� <br /> �Q 9 s«sF c.� c:is� <br /> D. ROCK LAYER DII�gNSIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = , <br /> (eov gpd x 0.83 sq.ft./gpd = �� sq. ft.+io�,=54�' <br /> 2 Selert width of rock layer(10 feet or less) = i o ft. <br /> 3. Length of rock layer =area=width= R�g� <br /> 5 4� sq. ft.i i u ft. = SS ft. ,.,.,.�.,.,.,.�.w,.,...',�.,.,., <br /> r•�.�•r•�•�•r•r•r�•�.r.r.r.r•� <br /> � ti•\•1•�N�M•t•wt•Mti•tiK�ti•�•� <br /> 1•f•1 N•t•d.t•J��N•�•r•M!•J•I• <br /> ti.ti•ti.�.�•ti.�•ti.�•ti.ti.ti.ti.ti.ti idth <_10 ft <br /> � 1�1:tiH�fti�Mf�tif�•�tiKhwftifti�� <br /> •r•f•f•I•f•I•�y.f•�•pr•r•1•f.f• <br /> E. ROCK VOLtTME ~— �'�' --� -- <br /> 1. Multiply rock area by rock depth to get cubic feet of rock; �� <br /> 5ti� sq. ft. x/_o s ft. = S�y cu.ft. <br /> 2 Divide cu.ft.by 27 cu. ft./cu. yd. to get cubic yards; <br /> <�y cu.ft. s 27= a 1_cu.yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> a i cu.yd.x 1.4 ton/cu.yd. _�tons. <br /> F. ADSORI'TTON WIDTH G�`� `-0'�"'1 <br /> ' Widd� ' ' Tabk <br /> 1. Percolation rate in top 12 inches of soil is /�. 1 mpi r�,ro,,,a,R„� �-- �1 <br /> �t;,,,,�pQ;�, Soii Texture �.r �� <br /> cmpi) r.. � <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oar�sana 12o i.00 <br /> ��-1 gpd/f t� 0.1 to 5 Sand 120 1.00 <br /> 0.1 to 5 Fne Sand" 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 152 <br /> 3. Calculate adso tion width ratio b dividin rock la er 16 to�o t.oam o.�o zoo <br /> rP Y g Y 31 to 4� silc t.oam oso 2•�0 <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �to�o c�a Loam. �� 2•6� <br /> 1.20 gPd/ft2�- �ti gpd/ft� = d.L7 Slowerthan120 �Y 024 5_00 <br /> "Sail h�vin�SOY.ar mQe d fn+e ar ve�Cu�e sand. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �.�� x /v ft=��,.� ft - <br /> �,� <br />