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1997-009114 - new septic
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0951 Spring Hill Road - 26-118-23-44-0002
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1997-009114 - new septic
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Entry Properties
Last modified
8/22/2023 4:19:03 PM
Creation date
3/7/2019 11:03:03 AM
Metadata
Fields
Template:
x Address Old
House Number
951
Street Name
Spring Hill
Street Type
Road
Address
951 Spring Hill Road
Document Type
Septic
PIN
2611823440002
Supplemental fields
ProcessedPID
Updated
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� � MOUND DESIGN WORKSHEET <br /> � ' ' ' (For Flows up to 1200 gpd) <br /> A. �.Qw Estirnated Sew�ge Floa in Gallo�s pa Day(gpd) ,.--� <br /> Estimated�Q_gpd N`o� ,ry�j .�,a i[ 7ype IIl �cya rv , <br /> or measured - x 1.5 = - gpd. s��� <br /> 2 soo zu �so � <br /> 3 450 300 218 � <br /> B. SEPTIC TANK LIQUID VOLUMES � + � 37S � ��.v <br /> 5 750 450 294 0 <br /> o�-�l7ba gdllO11S 6 900 525 332 �° <br /> 7 1050 600 370 �� <br /> 8 IZ00 675 408 <br /> C. SOILS(refer to site evaluation) � � <br /> 1. Depth to restricting layer= `� � u inches N� '�-,,`�` �,,� <br /> 2 Depth of peroolation tests = 1 '' inches `'""° `''""' <br /> 3. Percolation rate Z�� mpi 2;a'� ,'o�oo i''w�o <br /> 4. Land slope 4 % 7 a$ � ;�o <br /> �Q 9 s«e&c-s �x is� <br /> D. ROCK LAYER DIlv�1SIONS <br /> 1. Multiply flow rate by 0.83 to obtain required area of rock <br /> layer:A x 0.83 = o� <br /> (000 gpd x 0.83 sq. ft./gpd = ��_°1_s�_sq. ft-��a�o 5�� <br /> 2 Select width of rock layer(10 feet or less) _ /� ft. <br /> 3. Length of rock layer = area i width= R�g� <br /> Sy'1 sq. ft.�- �p_ft. = SS ft. �•�•ti•tiN•ti•MMMti•ti•1•�ti.�•ti.ti <br /> J•r.t•I•I•r•�Hr•1•�•r•r•t•t•I� <br /> tiN•�•ti•ti�1KH•Mti•tiK•t•ti•1•'►•ti <br /> f•t•r.!•�•f.t•t•r r•t•t•t•r•f•t• <br /> �•tiM•ti.tiM•MtiH.wti.1•ti•Y1•ti•ti �dth S10 ft. <br /> �l�/�f.�.f�f.r.f.f�f.r.��r.j�r.r• <br /> 1ftif�,Mf�ftij�Htif�ftifSftif�fti•�•ti•ti <br /> t r•1• <br /> E. ROCK VOLUME �- �'�' � f ) <br /> 1. Multiply rock azea by rock depth to get cubic feet of rock; �' <br /> �y2,sq.ft. x ,o ft. _�cu.ft. <br /> 2. Divide cu.ft.by 27 cu.ft./cu. yd. to get cubic yards; <br /> 5� cu. ft. i 27=�cu.yd. � <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons; <br /> �cu.yd.x 1.4 ton/cu. yd. _�tons. <br /> F. ADSORPTTON WIDTH ��q to v►� <br /> ' VKdth Sirin Tabk <br /> 1. Percolation rate in top 12 inches of soil is 2.1 mpi r�,ro,,ti�,wr � ;�M; <br /> M;,,,,��;�, Soil Texture �.q„� M",� <br /> (a abiseaa� <br /> �.�dd <br /> 2. Select allowable soil loading rate from table; Faster than 0.1 oa�sana 1.2o i.00 <br /> . '-1� gpd/ffi� 0.1 to5 Sand 1.20 1.00 <br /> 0.1 to 5 Fine Sand" 0.60 2.00 <br /> 6 to 15 ndy Loam 0.79 1S2 <br /> 3. Calculate adsorption width ratio by dividing rock layer si to as sil[.om o� 2.� <br /> loading rate of 1.20 gpd/ft2 by allowable soil loading rate; �-t 12 cla I'°am '45 ;:oo <br /> 1.20 gpd/ft2i .4S gpd/ftz= a� l07 Slowerthan 120 Cla -- - <br /> "Sail ltiving 505G ae mae d fine or vey fine sand. <br /> 4. Multiply adsorption width ratio by rock layer width to get <br /> required adsorption width; <br /> �,b7 x Iv ft=a�.� ft , <br /> ' .�✓ <br />
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