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septic design-2003
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Last modified
8/22/2023 5:02:11 PM
Creation date
3/6/2019 12:55:15 PM
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Template:
x Address Old
House Number
761
Street Name
Spring Hill
Street Type
Road
Address
761 Spring Hill Road
Document Type
Septic
PIN
3611823210005
Supplemental fields
ProcessedPID
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' ��MOUND DESIGN WORK SHEET(For Flows u to 1200 d) <br /> A. Average Design FLOW A-1: Estimated Sewa�e Flovvs in Gallons per Dcy <br /> nu r o <br /> Estimated r1��f� gpd(see figure A-1) bedroom: c�cu� c�ass u c�au m c�aas�v <br /> or measured x 1.5 (safety factor) = gpd 2 � 225 �8° � <br /> 3 . q5p 300 218 ofthe <br /> 4 600 375 256 values <br /> B. SEPTIC TANK Capacity 5 750 450 294 �n tne <br /> 6 900 525 332 Class I, <br /> 7 1050 600 370 II,or III <br /> I-1 aSo♦ 1-100 o gallons (see figure C-1) g �2pp 675 ao8 columns. <br /> { 1 ����M 1�'E- S\'t'f� Gl: Tank Ca tks bns <br /> C. SOILS (re�er to site evaluation) .'�' <br /> µ Nnmber of Minimum Li uid wd � W�� �9uid capaciry <br /> 1. Depth to restricting layer= /•(o. �.� feet <br /> '�3,4 � s�a�� c�cy9 �� W��n a►�a�� <br /> 2. Depth of percolation tests= /.c� feet �3`'� z a�� �� »u �sao <br /> 3. Texture LL-t4�`� ►,oY�w1 s o 6 is�oo ?�0 200° <br /> 3000 <br /> Percolation rate�,1•�_mpi �,8 019 � 3� <br /> 4. Soil loading rate .4S gpd/sqft(see figure D-33) <br /> 5. Percent land slope /[� % <br /> D. ROCK LAYER DIMENSIONS <br /> 1. Multiply average design flow (A)by 0.83 to obtain re9uired rock�ayer area. <br /> �SO gpd x 0.83 sqft/gpd = L a a� sqft t►�`��=��y� <br /> 2. Determine rock layer width = 0.83 sqft/gpd x linear Loading Rate (LLR <br /> 0.83 sqft/gpd x !Z gpd/sqft= 1a ft Mound LLR <br /> 3. Length of rock layer= area+width = <br /> 4�'� sqft(D1) + �_ft (D2) _��ft < � 2O M P I <� 2 <br /> E. ROCK VOLUME � � 2O MPI < 6 <br /> 1. Multi ly rock area (Dl)by rock depth of 1 ft to get cubic feet of rock <br /> �,�,sqft x 1 ft=��cuft <br /> 2. Divide cuft by 27 cuft/cuyd to get cubic yards <br /> ��cuft +27 cuyd/cuft=_�_cuyd <br /> 3. Multiply cubic yards by 1.4 to get weight of rock in tons <br /> �._cuyd x 1.4 ton/cuyd = �_tons <br /> D-33: ADeorption VVidth SlzfnQ Table <br /> percol��q�Rate L,oeding Rate <br /> F. SEWAGE ABSORPTION WIDTH inMinutaper sa�T�►,� c.��«u Absorption <br /> Inch per daY per Ratio <br /> ►�p� wtt foot <br /> Fetter than 3 Cwne Sard 1•ZO 1•00 <br /> Medium Sud <br /> Absorption width equals absorption ratio (See Figure D-33) `A""ys°"d <br /> times rock layer width (D2) '„0 4 „ . :< <br /> �,tI� X__1!z__.�_ ��• 1 t 46 to 60 Sil�t yG7�yYl.o�m 0.43 2.6'7 <br /> 61 to 120 S ilty Ga y 0.24 5.00 <br /> ud <br /> lowa ihan <br /> •Syqam dad`aW tor Nw wil�mm M abu or psrfemrnee � <br />
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